Tính \(15\frac{1}{4}:\left(\frac{-5}{7}\right)-25\frac{1}{4}:\left(\frac{-5}{7}\right)\)
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\(\left(\frac{2}{5}\right)^6.\left(\frac{25}{4}\right)^2\)
\(=\left[\left(\frac{2}{5}\right)^3\right]^2.\left(\frac{25}{4}\right)^2\)
\(=\left[\left(\frac{2}{5}\right)^3.\frac{25}{4}\right]^2\)
\(=\left[\frac{8}{125}.\frac{25}{4}\right]^2\)
\(=\left(\frac{2}{5}\right)^2\)
\(=\frac{4}{25}\)
\(15\frac{1}{5}:\left(\frac{-5}{7}\right)-25\frac{1}{5}.\left(\frac{-7}{5}\right)\)
\(=15\frac{1}{5}.\frac{-7}{5}-25\frac{1}{5}.\frac{-7}{5}\)
\(=\frac{-7}{5}\left(15\frac{1}{5}-25\frac{1}{5}\right)\)
\(=\frac{-7}{5}.\left(-10\right)\)
\(=14\)
Ta có: \(15\frac{1}{4}:\left(-\frac{5}{7}\right)-25\frac{1}{4}:\left(-\frac{7}{7}\right)\)
\(=\frac{61}{4}:\frac{-5}{7}+\frac{101}{4}\)
\(=\frac{61}{4}\cdot\frac{7}{-5}+\frac{101}{4}\)
\(=\frac{427}{-20}+\frac{101}{4}\)
\(=\frac{427}{-20}+\frac{-505}{-20}=\frac{-80}{-20}=4\)
15'1/4:(-5/7)-25'1/4:(-5/7)
=(15'1/4-25'1/4):(-5/7)
=-10:(-5/7)
=-10.(-7/5)
=-70/5=-14