help me khẩn cấp! pls
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Giả sử n=1
1x2x3x4=24
mà 24 ko là số chính phương
=>A = n(n+1)(n+2)(n+3) ko là số chính phương với mọi số m khác 0
a, 2KNO3 ----> 2KNO2 + O2
n KNO3= m/M= 60.6/101= 0.6 mol
n KNO3=1/2 n O2 => n O2= 0.6/2= 0.3 mol
b,V O2= n . 22.4 = 0.3 . 22.4 = 6.72 l
n Al= m/M= 13.5/27= 0.5 mol
4Al + 3O2 ----> 2Al2O3
Xét n Al : n O2 = n Al đề bài/ n Al phương trình : n O2 đề bài/ O2 phương trình= 0.5/4 : 0.3/3 = 0.125 > 0.1
=> O2 hết Al dư. Sản phẩm tính theo O2
=> n Al2O3= (0.3 .2)/3= 0.2 mol
Chất rắn thu được ngoài Al2O3 còn có Al dư.
n Al dư= 0.5-[(0.3 .4)/3] = 0.1 mol
=> m Al2O3= n.M= 0.2 . 102=20.4 g
m Al dư= n Al dư . M= 0.1 . 27= 2.7 g
GỌI SỐ ĐÓ LÀ A
Vì quên 2 chữ số 0 nên số mới là 22
a x 2002 = a x 22 + 3965940
a x 1980 = 3965940
a = 3965940 : 1980 = 2003
Vậy số đó là 2003
Gọi số đó là a
Vì quên viết 2 cs 0 nên Toàn định nhân a với 22
Ta có: a x 2002 = a x 22 + 3965940
a x 1980 = 3965940
a = 3965940 : 1980 = 2003
Vậy số đó là 2003
Tk me [khẩn cấp]
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1 Yesterday the plane took off earlier than I expected
2 My mother looks after us more carefully than my father
3 They cut the big cake into smaller parts than I thought
4 My sister even tells me off more often than my mother does
5 Who saw you off yesterday?
6 It is cold today so I put on more warm clothes than usual
7 Yesterday my mother picked my up later than usual
8 You are the pretties girl I have ever known
9 Unless you listen attentively to your teacher, you won't catch up with your friends
10 By far, "The Little Prince" has been my favorite book
39 be on time for your interview
40 tall is she
41 What is she like?
42 have you been in this city?
43 is the price of those books
44 How did she greet friends?
45 What did she walk to the station for
P = \(\sqrt{4+\sqrt{5\sqrt{3}+5\sqrt{48-10\sqrt{7+4\sqrt{3}}}}}\)
P = \(\sqrt{4+\sqrt{5\sqrt{3}+5\sqrt{48-10\sqrt{\left(2+\sqrt{3}\right)^2}}}}\)
P = \(\sqrt{4+\sqrt{5\sqrt{3}+5\sqrt{48-20-10\sqrt{3}}}}\)
P = \(\sqrt{4+\sqrt{5\sqrt{3}+5\sqrt{\left(5-\sqrt{3}\right)^2}}}\)
P = \(\sqrt{4+\sqrt{5\sqrt{3}+25-5\sqrt{3}}}=\sqrt{4+\sqrt{25}}=\sqrt{9}=3\)
Q = \(\left(\sqrt{3}-1\right)\sqrt{6+2\sqrt{2}.\sqrt{3-\sqrt{\sqrt{2}+\sqrt{12}+\sqrt{18-\sqrt{128}}}}}\)
Q = \(\left(\sqrt{3}-1\right)\sqrt{6+2\sqrt{2}.\sqrt{3-\sqrt{2+2\sqrt{3}+\sqrt{\left(16-8\sqrt{2}+2\right)}}}}\)
Q = \(\left(\sqrt{3}-1\right)\sqrt{6+2\sqrt{2}.\sqrt{3-\sqrt{\sqrt{2}+2\sqrt{3}+\sqrt{\left(4-\sqrt{2}\right)^2}}}}\)
Q = \(\left(\sqrt{3}-1\right)\sqrt{6+2\sqrt{2}.\sqrt{3-\sqrt{\sqrt{2}+2\sqrt{3}+4-\sqrt{2}}}}\)
Q = \(\left(\sqrt{3}-1\right)\sqrt{6+2\sqrt{2}.\sqrt{3-\sqrt{\left(\sqrt{3}+1\right)^2}}}\)
Q = \(\left(\sqrt{3}-1\right).\sqrt{6+2\sqrt{2}.\sqrt{3-\sqrt{3}-1}}\)
Q = \(\left(\sqrt{3}-1\right)\sqrt{6+2\sqrt{4-2\sqrt{3}}}\)
Q = \(\left(\sqrt{3}-1\right)\sqrt{6+2\sqrt{\left(\sqrt{3}-1\right)^2}}=\left(\sqrt{3}-1\right).\sqrt{6+2\sqrt{3}-2}\)
Q = \(\left(\sqrt{3}-1\right)\sqrt{4+2\sqrt{3}}=\left(\sqrt{3}-1\right)\sqrt{\left(\sqrt{3}+1\right)^2}=\left(\sqrt{3}-1\right)\left(\sqrt{3}+1\right)=3-1=2\)
D = \(\sqrt{2+\sqrt{3}+\sqrt{4-2\sqrt{3}-\sqrt{21-12\sqrt{3}}}}\)
D = \(\sqrt{2+\sqrt{3}+\sqrt{4-2\sqrt{3}-\sqrt{\left(2\sqrt{3}-3\right)^2}}}\)
D = \(\sqrt{2+\sqrt{3}+\sqrt{4-2\sqrt{3}-2\sqrt{3}+3}}\)
D = \(\sqrt{2+\sqrt{3}+\sqrt{\left(2-\sqrt{3}\right)^2}}\)
D = \(\sqrt{2+\sqrt{3}+2-\sqrt{3}}=\sqrt{4}=2\)
E = \(\sqrt{2-\sqrt{2\sqrt{5}-2}}-\sqrt{2+\sqrt{2\sqrt{5}-2}}\)
E2 = \(2-\sqrt{2\sqrt{5}-2}+2+\sqrt{2\sqrt{5}-2}-2\sqrt{\left(2-\sqrt{2\sqrt{5}-2}\right)\left(2+\sqrt{2\sqrt{5}-2}\right)}\)
E2 = \(4-2\sqrt{\left(4-2\sqrt{5}+2\right)}=4-2\sqrt{\left(\sqrt{5}-1\right)}^2=4-2\sqrt{5}+2=\left(\sqrt{5}-1\right)^2\)
=> E = \(\sqrt{\left(\sqrt{5}-1\right)^2}=\sqrt{5}-1\)