tính nhanh
A=\(\frac{2009x2010+2000}{2011x2010-2020}\)
giúp mình với nhanh lên nhé
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Ta có:
T = \(\frac{2009\times2010+2000}{2011\times2010-2020}=\frac{2009\times2010+2010-10}{2010\times2010+2010-2020}=\frac{2010\times2010-10}{2010\times2010-10}=1\)
Vậy T = 1
2009×2010+2000/2011×2010-2020
=2009×2010+2000/2009×2010+2×2010-2020
=2009×2010+2000/2009×2010+4020-2020
=2000/4020-2020
=2000/2000
=1
K đúng cho mk nha !!!
\(t=\frac{2009.2010+2000}{2011.2010-2020}\)
\(t=\frac{2009.2010+2000}{\left(2009+2\right).2010-2020}\)
\(t=\frac{2009.2010+2000}{2009.2010+2.2010-2020}\)
\(t=\frac{2009.2010+2000}{2009.2010+2000}=1\)
\(q=\frac{\text{2014.2015+2010}}{2016.2015-2020}\)
\(q=\frac{\text{2014.2015+2010}}{\left(2014+2\right).2015-2020}\)
\(q=\frac{\text{2014.2015+2010}}{2014.2015+2.2015-2020}\)
\(q=\frac{\text{2014.2015+2010}}{\text{2014.2015+2010}}=1\)
Lời giải:
$t=\frac{2009\times 2010+2000}{2011\times 2010-2020}$
$=\frac{2010\times (2011-2)+2000}{2011\times 2010-2020}$
$=\frac{2010\times 2011-2\times 2010+2000}{2011\times 2010-2020}$
$=\frac{2010\times 2011-2020}{2011\times 2010-2020}=1$
2009x2010+2011x12+1998
2011x2010-2010x 2009
=2009x2010+2010x12+12+1998
2010x(2011-2009)
=2010x2009+2010x12+2010x1
2010x2
=2010x(2009+12+1)
2010x2
=2010x2022
2010x2
=2022
2
=1011
\(=\frac{\left(2009-1\right)\cdot2009+2000}{2009\cdot\left(2009+1\right)-2018}=\frac{2009^2-9}{2009^2-9}=1\\ \)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{2010}-\frac{1}{2011}\)
\(=1-\frac{1}{2011}\)
\(=\frac{2010}{2011}\)
=1/1-1/2+1/2-1/3+1/3-1/4+...+1/2010-1/2011
= 1 - 1/2011
= 2010/ 2011
Đáp số: 2010/2011
Chúy ý công thức: \(\frac{1}{n\left(n+1\right)}=\frac{1}{n}-\frac{1}{n+1}\)
A = -[-506+732-(-2000)]-(506-1732)
A = -[ 226 -(-2000)]-( -1226)
A = -2226 -( -1226)
A = -1000
\(A=\frac{2009x2010+2000}{2011x2010-2020}=\frac{2009x2010+2000}{2009x2010+2x2010-2020}=\frac{2009x2010+2000}{2009x2010+4020-2020}=\frac{2000}{4020-2020}=\frac{2000}{2000}=1\)
Nhấn đúng cho mk nha!!!!!!!!!!