Tính bằng cách thuận tiện nhất
a, 739x2+739+739x3+739x4
b, 1/7 + 2/7 + 3/7 + 4/7 + 5/7 + 6/7
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A. 64 : 16 = 4
B. 210 : 30 = 7
C. 504 : 56 = 9
D. 115 : 23 = 5
a) \(\dfrac{3}{5}\times\dfrac{17}{21}+\dfrac{17}{21}\times\dfrac{2}{5}\)
\(=\dfrac{17}{21}\times\left(\dfrac{3}{5}+\dfrac{2}{5}\right)\)
\(=\dfrac{17}{21}\times1\)
\(=\dfrac{17}{21}\)
b) \(\dfrac{15}{8}:\dfrac{5}{20}-\dfrac{7}{8}:\dfrac{1}{4}\)
\(=\dfrac{15}{8}\times\dfrac{20}{5}-\dfrac{7}{8}\times4\)
\(=\dfrac{15}{8}\times4-\dfrac{7}{8}\times4\)
\(=4\times\left(\dfrac{15}{8}-\dfrac{7}{8}\right)\)
\(=4\times1\)
\(=4\)
\(\dfrac{8}{13}+\dfrac{4}{9}+\dfrac{1}{3}+\dfrac{5}{13}+3\)
\(=1+\dfrac{7}{9}+3\)
\(=4+\dfrac{7}{9}=\dfrac{43}{9}\)
`39/16 : 5/8 - 7/16 : 5/8`
`=39/16 xx 8/5- 7/16 xx 8/5`
`=8/5 xx (39/16 - 7/16)`
`= 8/5 xx2`
`= 16/5`
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` 4/3 xx 9/8 - 4/3 xx 3/8`
`=4/3 -(9/8 - 3/8)`
`= 4/3 xx 3/4`
`=1`
\(a,\\ \dfrac{39}{16}:\dfrac{5}{8}-\dfrac{7}{16}:\dfrac{5}{8}\\ =\dfrac{39}{16}\cdot\dfrac{8}{5}-\dfrac{7}{16}\cdot\dfrac{8}{5}\\ =\dfrac{8}{5}\cdot\left(\dfrac{39}{16}-\dfrac{7}{16}\right)=\dfrac{8}{5}\cdot2=\dfrac{16}{5}\\ b,\\ \dfrac{4}{3}\cdot\dfrac{9}{8}-\dfrac{4}{3}\cdot\dfrac{3}{8}=\dfrac{3}{2}-\dfrac{1}{2}=1\)
\(\dfrac{1}{7}+\dfrac{2}{7}+\dfrac{3}{7}+\dfrac{4}{7}+\dfrac{5}{7}+\dfrac{6}{7}\)
\(=\dfrac{1+2+3+4+5+6}{7}=3\)
\(\dfrac{1}{7}+\dfrac{2}{7}+\dfrac{3}{7}+\dfrac{4}{7}+\dfrac{5}{7}+\dfrac{6}{7}\)
\(=\left(\dfrac{1}{7}+\dfrac{6}{7}\right)+\left(\dfrac{2}{7}+\dfrac{5}{7}\right)+\left(\dfrac{3}{7}+\dfrac{4}{7}\right)\)
\(=1+1+1\)
\(=3\)
\(a,1999-2000+1=\left(1999+1\right)-2000=2000-2000=0\\ b,450:5+550:5=\left(450+550\right):5=1000:5=200\\ c,188\times7+188\times4-188=188\times\left(7+4-1\right)=188\times10=1880\)
a,1999−2000+1=(1999+1)−2000=2000−2000=0b,450:5+550:5=(450+550):5=1000:5=200c,188×7+188×4−188=188×(7+4−1)=188×10=1880
a) 739 x 2 + 739 + 739 x 3 + 739 x 4
= 739 x 2 + 739 x 1 + 739 x 3 + 739 x 4
= 739 x ( 2 + 1 + 3 + 4 )
= 739 x 10
= 7390
b) \(\frac{1}{7}\) + \(\frac{2}{7}\) + \(\frac{3}{7}\)+ \(\frac{4}{7}\) + \(\frac{5}{7}\) + \(\frac{6}{7}\)
= ( \(\frac{1}{7}\) + \(\frac{6}{7}\) ) + ( \(\frac{2}{7}\) + \(\frac{5}{7}\) ) + ( \(\frac{3}{7}\)+ \(\frac{4}{7}\) )
= \(1\) \(+\) \(1\) \(+\) \(1\)
= \(3\)
~ Hok T ~