\((-2)^6 . 3^7 . 16 /6^4 . 2^5 . 9\)
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a. \(\dfrac{656565}{272727}=\dfrac{65}{27}\)
b. \(\dfrac{2}{7}\left(\dfrac{3}{4}+\dfrac{9}{4}\right)=\dfrac{6}{7}\)
a)
\(\dfrac{6}{12}=\dfrac{6:6}{12:6}=\dfrac{1}{2}\)
\(\Rightarrow\dfrac{1}{2}=\dfrac{1\times2}{2\times2}=\dfrac{2}{4}\)
Mà \(\dfrac{2}{4}< \dfrac{3}{4}\)
Vậy \(\dfrac{6}{12}< \dfrac{3}{4}\).
b)
\(\dfrac{8}{10}=\dfrac{8:2}{10:2}=\dfrac{4}{5}\)
Mà \(\dfrac{2}{5}< \dfrac{4}{5}\)
Vậy \(\dfrac{2}{5}< \dfrac{8}{10}\).
c)
\(\dfrac{40}{35}=\dfrac{40:5}{35:5}=\dfrac{8}{7}\)
Mà \(\dfrac{8}{7}>\dfrac{6}{7}\)
Vậy \(\dfrac{40}{35}>\dfrac{6}{7}\).
d)
\(\dfrac{8}{16}=\dfrac{8:8}{16:8}=\dfrac{1}{2}\)
Mà \(\dfrac{1}{2}< \dfrac{5}{2}\)
Vậy \(\dfrac{8}{16}< \dfrac{5}{2}\).
Ta có: \(\frac{5^2\cdot6^{11}\cdot16^2+6^2\cdot12^6\cdot15^2}{4^7\cdot5^2\cdot9^5}\)
\(=\frac{5^2\cdot2^{11}\cdot3^{11}\cdot2^8+2^2\cdot3^2\cdot2^{12}\cdot3^6\cdot3^2\cdot5^2}{2^{14}\cdot3^{10}\cdot5^2}\)
\(=\frac{2^{19}\cdot3^{11}\cdot5^2+2^{14}\cdot3^{10}\cdot5^2}{2^{14}\cdot3^{10}\cdot5^2}=\frac{2^{14}\cdot3^{10}\cdot5^2\left(2^5\cdot3+1\right)}{2^{14}\cdot3^{10}\cdot5^2}\)
\(=2^5\cdot3+1=32\cdot3+1=96+1=97\)
\(\frac{\left(-2\right)^6\cdot3^7\cdot16}{6^4\cdot2^5\cdot9}\)
\(=\frac{2^6\cdot3^7\cdot2^4}{2^4\cdot3^4\cdot2^5\cdot3^2}\)
\(=\frac{2^{10}\cdot3^7}{2^9\cdot3^6}=2\cdot3=6\)
\(\text{Chúc bạn học tốt !}\)
\(\frac{\left(-2\right)^6.3^7.16}{6^4.2^5.9}\)
\(=\frac{2^6.3^7.2^4}{2^4.3^4.2^5.3^2}\)
\(=\frac{2^{10}.3^7}{2^9.3^6}=2.3=6\)