118,24-(8X=5+Xx3)=27,12x2
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118,24-(X:5+Xx3)=54,24
118,24-x:(5+1/3)=54,24
118,24-x:16/3=54,24
x:16/3=64
x=1024/3
Vậy x=1024/3
\(118,24-\left(x:5+x.3\right)=54,24\)
\(\Rightarrow118,24-\left(x.0,2+x.3\right)=54,24\)
\(\Rightarrow118,24-\left[x.\left(0,2+3\right)\right]=54,24\)
\(\Rightarrow118,24-3,2x=54,24\)
\(\Rightarrow3,2x=118,24-54,24\)
\(\Rightarrow3,2x=64\)
\(\Rightarrow x=64:3,2\)
\(\Rightarrow x=20\)
Vậy x=20
Chúc bn học tốt
\(118,24-\left(y\cdot3+y:5\right)=54,24\)
=>\(\left(y\cdot3+y\cdot0,2\right)=118,24-54,24\)
=>\(y\cdot3,2=64\)
=>\(y=\dfrac{64}{3,2}=20\)
118,24 - (x:5+x.3)= 54,24
x:5 + x.3 = 118,24 - 54,24 = 64
1/5 x + 15/5 x = 64
16/5 x = 64
x = 64 : 16/5 = 20
118,24 - ( x : 5 - x x 3 ) = 27,12 x 2
118,24 - ( x : 5 - x x 3 ) = 54,24
x : 5 - x x 3 = 118,24 - 54,24
x : 5 - x x 3 = 64
1/5x + 15/5x = 64
16/5x = 64
x = 64 : 16/5 = 20 = > x = 20
118,24 - ( \(x\)x \(\frac{1}{5}\)+ \(x\)x 3 ) = 54,24
\(x\)x ( \(\frac{1}{5}\)+ 3 ) = 118,24 - 54,24
\(x\)x \(\frac{16}{5}\) = 64
\(x\) = 64 : \(\frac{16}{5}\)
\(x\) = 20
\(118,24-\left(x:5+x.3\right)=27,12.2\)
\(\Leftrightarrow118,24-\left(x:5+x.3\right)=54,24\)
\(\Leftrightarrow x:5+x.3=118,24-54,24\)
\(\Leftrightarrow x.\frac{1}{5}+x.3=64\)
\(\Leftrightarrow x.\left(\frac{1}{5}+3\right)=64\)
\(\Leftrightarrow x.\frac{16}{5}=64\)
\(\Leftrightarrow x=64:\frac{16}{5}\)
\(\Leftrightarrow x=20\)