\(\frac{4}{7}\) + \(\frac{1}{7}\).\(\frac{2}{3}\)-\(\frac{1}{7}\).\(\frac{5}{2}\)
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\(=\frac{5}{4}.\left(-\frac{1}{3}+-\frac{1}{3}+\frac{3}{7}+\frac{4}{7}\right)=\frac{5}{4}.0=0\)
\(=\frac{9}{5}\left(-\frac{3}{22}+-\frac{3}{5}\right)=-\frac{729}{550}\)
\(\left(\frac{3}{4}-\frac{13}{11}+\frac{7}{5}\right)-\left(3-\frac{1}{2}-\frac{35}{11}\right)+\left(\frac{11}{4}-\frac{2}{5}\right)\)
= \(\frac{3}{4}-\frac{13}{11}+\frac{7}{5}-3+\frac{1}{2}+\frac{35}{11}+\frac{11}{4}-\frac{2}{5}\)
= \(\left(\frac{3}{4}+\frac{11}{4}+\frac{1}{2}\right)\left(-\frac{13}{11}+\frac{35}{11}\right)+\left(\frac{7}{5}-\frac{2}{5}\right)-3\)
= \(8+2+1-3\)
= \(8\)
#)Giải :
\(\left(\frac{3}{4}-\frac{13}{11}+\frac{7}{5}\right)-\left(3-\frac{1}{2}-\frac{35}{11}\right)+\left(\frac{11}{4}-\frac{2}{5}\right)\)
\(=\frac{3}{4}-\frac{13}{11}+\frac{7}{5}-3+\frac{1}{2}+\frac{35}{11}+\frac{11}{4}-\frac{2}{5}\)
\(=\left(\frac{3}{4}+\frac{11}{4}\right)+\left(-\frac{13}{11}+\frac{35}{11}\right)+\left(\frac{7}{5}-\frac{2}{5}\right)-3+\frac{1}{2}\)
\(=\frac{7}{2}+2+1-3+\frac{1}{2}\)
\(=\frac{7}{2}+\frac{1}{2}\)
\(=4\)
1/4+2/5+6/8+2/15+6/7
=(1/4+6/8)+(2/5+2/15)+6/7
=(2/8+6/8)+(6/15+2/15)+6/7
=1+8/15+6/7
=1+56/105+90/105
=1+146/105
=1+105/105+41/105
=1+1+41/105
=2+41/105
=2 và 41/105
2 và 41/105 là hỗn số nha
1/4+2/5+6/8+2/15+6/7
Ta có:
1/4=1-3/4
6/8=3/4
2/15=2/3*5=1/3-1/5
==> 1-3/4+2/5+3/4+1/3-1/5+6/7
=1+1/3+1/5+6/7
=(105+35+21+90)/105
=251/105.
ta có
đặt 3/5+3/7-3/11=N=> N=3*(1/5+1/7-1/11)
đặt 4/5+4/7-4/11=P=> P=4*(1/5+1/7-1/11)
=> N/P=3*(1/5+1/7-1/11)/4*(1/5+1/7-1/11)=> M=3/4
Bài này dễ mà!
Ta có : \(C=\frac{\frac{1}{3}-\frac{1}{7}-\frac{1}{13}}{\frac{2}{3}-\frac{2}{7}-\frac{2}{13}}\cdot\frac{\frac{1}{3}-0,25+0,2}{1\frac{1}{6}-0,875+0,7}+\frac{6}{7}\)
\(\Rightarrow C=\frac{\frac{1}{3}-\frac{1}{7}-\frac{1}{13}}{2\left(\frac{1}{3}-\frac{1}{7}-\frac{1}{13}\right)}\cdot\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{6}-\frac{7}{8}+\frac{7}{10}}+\frac{6}{7}\)
\(\Rightarrow C=\frac{1}{2}\cdot\frac{2\left(\frac{1}{6}-\frac{1}{8}+\frac{1}{10}\right)}{7\left(\frac{1}{6}-\frac{1}{8}+\frac{1}{10}\right)}+\frac{6}{7}\)
\(\Rightarrow C=\frac{1}{2}.\frac{2}{7}+\frac{6}{7}=\frac{1}{7}+\frac{6}{7}=1\)
Nhớ t.i.c.k đúng nha!
A=\([\)\(\frac{2}{7}\)\(\times\)(\(\frac{1}{4}-\frac{1}{3}\))\(]\)\(\div\)\([\)(\(\frac{2}{7}\times\)(\(\frac{3}{9}-\frac{2}{5}\))\(]\)
=(\(\frac{2}{7}\times\)\(\frac{-1}{12}\))\(\div(\)\(\frac{2}{7}\times\)\(\frac{-1}{15}\))
=\(\frac{-1}{42}\)\(\div\)\(\frac{-2}{35}\)
=\(\frac{-1}{42}\)\(\times\)\(\frac{35}{-2}\)
=\(\frac{5}{12}\)
\(\frac{4}{7}+\frac{1}{7}\times\frac{2}{3}-\frac{1}{7}\times\frac{5}{2}\)
\(=\frac{4}{7}+\frac{1}{7}\text{}\text{}\times\left(\frac{2}{3}-\frac{5}{2}\right)\)
\(=\frac{4}{7}+\frac{1}{7}\text{}\text{}\times\frac{-11}{6}\)
\(=\frac{4}{7}+\frac{-11}{42}\)
\(=\frac{13}{42}\)
_Chúc bạn học tốt
mục đích để kb