tính nhanh:3+7+11+...+186+190
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\(...=-\dfrac{4}{7}-\dfrac{3}{11}+\dfrac{3}{11}-\dfrac{3}{7}=-\dfrac{4}{7}-\dfrac{3}{7}=-1\)
-(4/7 + 3/11) - (-3/11 + 3/7)
= (-4/7) + (-3/11) - (-3/11) - 3/7
= [(-4/7) - 3/7)] + [(-3/11) - (-3/11)]
= -1 + 0
= -1
Bài 1 :
\(\frac{2}{19}+\frac{4}{5}+1\frac{7}{9}+\frac{1}{5}\)
\(=\frac{2}{19}+1\frac{7}{9}+\left(\frac{4}{5}+\frac{1}{5}\right)\)
\(=\frac{2}{19}+1\frac{7}{9}+1\)
\(=\frac{493}{171}\)
\(\frac{1}{11}+\frac{2}{11}+\frac{3}{11}+\frac{4}{11}+\frac{5}{11}+\frac{6}{11}+\frac{7}{11}+\frac{8}{11}+\frac{9}{11}+\frac{10}{11}\)
\(=\left(\frac{1}{11}+\frac{10}{11}\right)+\left(\frac{2}{11}+\frac{9}{11}\right)+\left(\frac{3}{11}+\frac{8}{11}\right)+\left(\frac{4}{11}+\frac{7}{11}\right)+\left(\frac{5}{11}+\frac{6}{11}\right)\)
\(=1+1+1+1+1\)
\(=5\)
Bài 2 :
y : (23 + 27) = 9 1000 : (y x 25) = 8
y : 50 = 9 y x 25 = 1000 : 8
y = 9 x 50 y x 25 = 125
y = 450 y = 125 : 25
133 : (190 : y) = 7 y = 5
190 : y = 133 : 7 450 : (y + 42) = 9
190 : y = 19 y + 42 = 450 : 9
y = 190 : 19 y + 42 = 50
y = 10 y = 50 - 42
y = 8
\(A=\frac{7}{11}\cdot\frac{-39}{190}\cdot\frac{76}{21}=\frac{-39\cdot7\cdot76}{11\cdot190\cdot21}=\frac{-273}{550}\)
B=\(\left(\frac{5}{8}+\frac{4}{5}\right)\)\(\cdot\left(2-\frac{2}{107}\right)\)
=>B=\(\frac{57}{40}\cdot\frac{212}{107}=\frac{57\cdot212}{40\cdot107}=\frac{3021}{1070}\)
`#25080409`
\(\dfrac{6}{11}\times\dfrac{3}{7}+\dfrac{3}{7}\times\dfrac{5}{11}?\)
`=`\(\left(\dfrac{6}{11}+\dfrac{5}{11}\right)\times\dfrac{3}{7}\)
`=`\(\dfrac{11}{11}\times\dfrac{3}{7}=1\times\dfrac{3}{7}=\dfrac{3}{7}\)
\(\frac{\frac{3}{5}+\frac{3}{7}+\frac{3}{11}}{\frac{4}{5}+\frac{4}{7}+\frac{4}{11}}\)\(=\frac{3.\left(\frac{1}{5}+\frac{1}{7}+\frac{1}{11}\right)}{4.\left(\frac{1}{5}+\frac{1}{7}+\frac{1}{11}\right)}=\frac{3}{4}\)
3 + 7 + 11 + ... + 186 + 190
SSh cua day so la : (190 - 3) : 4 + 1 = 47,75
:V
( 190 - 3 ) : 4 + 1 = 47,75
Cô giáo mik bảo thế nhé ^ ^
Chúc bạn học tốt "