\(\frac{4^{1007}.9^{1007}}{3^{2015}.2^{2016}}\)
giúp mk nhé . mai mk phải nộp òi!
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
NN
1
17 tháng 10 2016
\(\frac{4^{1007}.9^{1007}}{3^{2015}.16^{503}}=\frac{4^{1007}.\left(3^2\right)^{1007}}{3^{2015}.\left(4^2\right)^{503}}=\frac{4^{1007}.3^{2014}}{3^{2015}.4^{1006}}=\frac{4}{3}\)
22 tháng 6 2018
a) \(\frac{3}{4}-\frac{2}{5}.x=x\)
\(\Rightarrow\frac{-2}{5}.x-x=\frac{-3}{4}\)
\(x.\left(\frac{-2}{5}-1\right)=\frac{-3}{4}\)
\(x.\frac{-7}{5}=\frac{-3}{4}\)
\(x=\frac{-3}{4}:\left(\frac{-7}{5}\right)\)
\(x=\frac{15}{28}\)
b) (2x-1).(3x-1/5).(4-2x) = 0
=> 2x - 1 = 0 => 2x = 1 => x = 1/2
3x-1/5 = 0 => 3x = 1/5 => x = 1/15
4-2x = 0 => 2x = 4 => x = 2
KL: x = 1/2 hoặc x = 1/15 hoặc x = 2
LH
4
NB
0
LT
15 tháng 3 2020
\(\frac{x+2}{2017}+\frac{x+3}{2016}+\frac{x+4}{2015}+\frac{x+5}{1007}+\frac{x+2074}{11}=0\)
\(\Leftrightarrow\frac{x+2}{2017}+1+\frac{x+3}{2016}+1+\frac{x+4}{2015}+1+\frac{x+5}{1007}+2+\frac{x+2074}{11}-5=0\)
\(\Leftrightarrow\frac{x+2019}{2017}+\frac{x+2019}{2016}+\frac{x+2019}{2015}+\frac{x+2019}{1007}+\frac{x+2019}{11}=0\)
\(\Leftrightarrow\left(x+2019\right)\left(\frac{1}{2017}+\frac{1}{2016}+\frac{1}{2015}+\frac{1}{1007}+\frac{1}{11}\right)=0\)
\(\Leftrightarrow\left(x+2019\right)=0vì\left(\frac{1}{2017}+\frac{1}{2016}+\frac{1}{2015}+\frac{1}{1007}+\frac{1}{11}\right)\ne0\)
\(\Leftrightarrow x=-2019\)
LC
7 tháng 1 2016
=2015-(2015-2016)-2016+22017-2015-22015/22014-(1-4)-3-(5+6)+11
=(2015-2015)+(2016-2016)+22-2+3-3-11+11
=0+0+(4-2)+(3-3)-(11-11)
=2
PT
2
\(\frac{4^{1007}.9^{1007}}{3^{2015}.2^{2016}}=\frac{\left(2^2\right)^{1007}.\left(3^2\right)^{1007}}{3^{2015}.2^{2016}}\)
\(=\frac{2^{2014}.3^{2014}}{3^{2015}.2^{2016}}=\frac{2^{2014}.3^{2014}}{3^{2014}.2^{2014}.3.2^2}\)
\(=\frac{1}{3.2^2}=\frac{1}{3.4}=\frac{1}{12}\)
Rút gọn
\(\frac{4^{1007}\cdot9^{1007}}{3^{2015}\cdot2^{2016}}=\frac{\left(2^2\right)^{2007}\cdot\left(3^2\right)^{1007}}{3^{2015}\cdot2^{2016}}\)
\(=\frac{2^{2\cdot1007}\cdot3^{2\cdot1007}}{3^{2015}\cdot2^{2016}}=\frac{2^{2014}\cdot3^{2014}}{3^{2015}\cdot2^{2016}}\)
\(=\frac{1}{3.2^2}=\frac{1}{12}\)
Vậy ...
hok tót .