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a) Ta có:
\(2^{300}=2^{3\cdot100}=\left(2^3\right)^{100}=8^{100}\)
\(3^{200}=3^{2\cdot100}=\left(3^2\right)^{100}=9^{100}\)
Mà: \(8< 9\)
\(\Rightarrow8^{100}< 9^{100}\)
\(\Rightarrow2^{300}< 3^{200}\)
b) Ta có:
\(3^{500}=3^{5\cdot100}=\left(3^5\right)^{100}=243^{100}\)
\(7^{300}=7^{3\cdot100}=\left(7^3\right)^{100}=343^{100}\)
Mà: \(243< 343\)
\(\Rightarrow243^{100}< 343^{100}\)
\(\Rightarrow3^{500}< 7^{300}\)
c) Ta có:
\(8^5=\left(2^3\right)^5=2^{3\cdot5}=2^{15}=2\cdot2^{15}\)
\(3\cdot4^7=3\cdot\left(2^2\right)^7=3\cdot2^{2\cdot7}=3\cdot2^{14}\)
Mà: \(2< 3\)
\(\Rightarrow2\cdot2^{14}< 3\cdot2^{14}\)
\(\Rightarrow8^5< 3\cdot4^7\)
d) Ta có:
\(202^{303}=202^{3\cdot101}=\left(202^3\right)^{101}=8242408^{101}\)
\(303^{202}=303^{2\cdot101}=\left(303^2\right)^{101}=91809^{101}\)
Mà: \(8242408>91809\)
\(\Rightarrow8242408^{101}>91809^{101}\)
\(\Rightarrow202^{303}>303^{202}\)
Câu 1:
1; 125 : 52
= 53 : 52
= 51
2; 275 : 813
= (33)5 : (34)3
= 315 : 312
= 33
3; 84.165.32
= (23)4.(24)5.25
= 212.220.25
= 237
Câu 1
4; 274.8110
= (33)4.(34)10
= 312.340
= 352
Câu 1.9920và 999910
=(992)10=980110
Vậy 980110<999910 suy ra 9920<999910
Câu 2. 3500và 7300
3500=(35)100=243100
7300=(73)100=343100
Vậy 243100<343100 => 3500<7300
a)\(27^2\)và \(4^6\)
\(27^2=\left(3^3\right)^2\)
\(4^6=\left(2^3\right)^2\)
\(3^3>2^3\)
b) \(3^{500}=\left(3^5\right)^{100}\)
\(7^{300}=\left(7^3\right)^{100}\)
\(7^3=343\)
\(3^5=243\)
\(\Rightarrow3^{500}< 7^{300}\)
c) \(8^5=4^5\cdot2^5\)
\(3\cdot4^7=3\cdot4^2\cdot4^5\)
\(3\cdot4^2>2^5\)
\(3\cdot4\cdot4=2\cdot2\cdot2\cdot2\cdot3>2\cdot2\cdot2\cdot2\cdot2\)
\(8^5< 3\cdot4^7\)
d) \(202^{303}=\left(202^3\right)^{101}\)
\(303^{202}=\left(303^2\right)^{101}\)
\(202^3>303^2\)
Nên
\(5^{200}=5^{2\times100}=\left(5^2\right)^{100}=25^{100}\)
\(2^{500}=2^{5\times100}=\left(2^5\right)^{100}=32^{100}\)
vì 32>25 nên 32100>25100 hay 2500 > 5200
\(3^{200}=3^{2\times100}=\left(3^2\right)^{100}=9^{100}\)
\(2^{300}=2^{3\times100}=\left(2^3\right)^{100}=8^{100}\)
vì 9>8 nên 9100>8100 hay 3200>2300
a/
\(2^{1050}=\left(2^2\right)^{525}=4^{525}< 5^{525}< 5^{540}\)
b/
\(2^{161}>2^{160}=\left(2^4\right)^{40}=16^{40}>13^{40}\)
c/
\(17^{14}>16^{14}=\left(2^4\right)^{14}=2^{56}>2^{55}=\left(2^5\right)^{11}=32^{11}>31^{11}\)
a, 2^300 < 3^200
b, 3^500 < 7^300
c, 8^5 > 3.4^7
d, 202^303 < 303^202
A) Ta có : 2300=23.100=(23)100=8100
3200=32.100=(32)100=9100
Vì 8100<9100
Nên 2300<3200
B)Ta có: 3500 =35.100=(35)100=243100
7300=73.100=(73)100=343100
Vì 243100<343
Nên 3500<7300