1 + 32 + 45 +20 =
90 + 64 + 32 =
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\(\dfrac{90}{120}=\dfrac{30.3}{30.4}=\dfrac{3}{4}\)
\(\dfrac{15}{25}=\dfrac{5.3}{5.5}=\dfrac{3}{5}\)
\(\dfrac{18}{45}=\dfrac{9.2}{9.5}=\dfrac{2}{5}\)
\(\dfrac{36}{64}=\dfrac{4.9}{4.16}=\dfrac{9}{16}\)
\(\dfrac{32}{72}=\dfrac{8.4}{8.9}=\dfrac{4}{9}\)
\(\dfrac{84}{49}=\dfrac{7.12}{7.7}=\dfrac{12}{7}\)
\(\dfrac{90}{120}=\dfrac{3}{4};\dfrac{15}{25}=\dfrac{3}{5};\dfrac{18}{45}=\dfrac{2}{5};\dfrac{36}{64}=\dfrac{9}{16};\dfrac{32}{72}=\dfrac{4}{9};\dfrac{84}{49}=\dfrac{12}{7}\)
Lời giải chi tiết:
28 < 31 | 84 < 90 | 54 < 50 + 5 |
65 > 64 | 72 = 72 | 25 = 20 + 5 |
23 < 32 | 48 > 39 | 86 < 80 + 7 |
28 < 31 | 84 < 90 | 54 < 50 + 5 |
65 > 64 | 72 = 72 | 25 = 20 + 5 |
23 < 32 | 48 > 39 | 86 < 80 + 7 |
Lời giải chi tiết:
20 + 60 = 80 | 60 + 4 = 64 | 30 + 2 = 32 |
80 – 20 = 60 | 64 – 4 = 60 | 32 – 2 = 30 |
80 – 60 = 20 | 64 – 60 = 4 | 32 – 30 = 2 |
20 + 30 = 50
90 + 32 = 122
45 + 65 = 110
48 + 29 = 77
34 + 58 = 92
32 x 25 +32 x 5 + 32 x 20 +32 x 45 +15 x 32 =32 x (25 + 5 + 20 + 45 + 15)
=32 x 110
=3520
Bài 3:
a: Ta có: \(23\left(42-x\right)=23\)
\(\Leftrightarrow42-x=1\)
hay x=41
b: Ta có: 15(x-3)=30
nên x-3=2
hay x=5
Bài 1:
a: 32+89+68=100+89=189
b: 64+112+236=300+112=412
c: \(1350+360+650+40=2000+400=2400\)
a) 560 : 20 = 28 560 : 2 = 280 | b) 450 : 90 = 5 4 500 : 90 = 50 | c) 400 : 50 = 8 4 000 : 50 = 80 |
a: \(A=\dfrac{1}{2}+\left(\dfrac{1}{2}\right)^2+\left(\dfrac{1}{2}\right)^3+...+\left(\dfrac{1}{2}\right)^7\)
=>\(2\cdot A=1+\dfrac{1}{2}+\left(\dfrac{1}{2}\right)^2+...+\left(\dfrac{1}{2}\right)^6\)
=>\(2A-A=1-\left(\dfrac{1}{2}\right)^7=1-\dfrac{1}{128}=\dfrac{127}{128}\)
=>\(A=\dfrac{127}{128}\)
b: \(B=\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{10\cdot11}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{10}-\dfrac{1}{11}\)
\(=1-\dfrac{1}{11}=\dfrac{10}{11}\)
= 98
=186
Trả lời:
1 + 32 + 45 + 20 = 98
90 + 64 + 32 = 186