| 2 | + | 2 | + … + | 2 | = | |
| 8 . 9 | 9 . 10 | 83 . 84 |
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HT
0
PT
1
CM
27 tháng 11 2019
15 + 2 + 1 = 18 68 - 1 - 1 = 66 77 - 7 - 0 = 70
34 + 1 + 1 = 36 84 - 2 - 2 = 80 99 - 1 - 1 = 97
25 tháng 1 2022
1: =-3x5+2x5-7x5+7x4=-8x5+7x4=-40+28=-12
2: =-3x5+3x6-4x3+4x2=-9+8=-1
3: =17(-84-16)=-1700
4: =1975(-115+15)=-197500
5: =-145x13+145x57+57x10-57x145=-1315
KV
25 tháng 1 2022
1/ \(5\left(-3+2\right)-7\left(5-4\right)\)
\(=5.\left(-3\right)+5.2-7.5-7.\left(-4\right)\)
\(=-15+10-35+28\)
\(=-5-7\)
\(=-12\)
2/ \(3.\left(-5+6\right)-4.\left(3-2\right)\)
\(=3.\left(-5\right)+3.6-4.3-4.\left(-2\right)\)
\(=-15+18-12+8\)
\(=3-4\)
\(=-1\)
3/ \(17.\left(-84\right)+17.\left(-16\right)\)
\(=17.\left(-84-16\right)\)
\(=17.\left(-100\right)\)
\(=-1700\)
4/ \(1975.\left(-115\right)+1975.15\)
\(=1975.\left(-115+15\right)\)
\(=1975.\left(-100\right)\)
\(=-197500\)
5/ \(-145.\left(13-57\right)+57.\left(10-145\right)\)
\(=-145.13-145.\left(-57\right)+57.10+57.\left(-145\right)\)
\(=-145.\left(-57+57\right)-145.13+57.10\)
\(=0-1885+570\)
\(=-1315\)
6/ \(157.17-157.7\)
\(=157.\left(17-7\right)\)
\(=157.10\)
\(=1570\)
7/ \(199.\left(15-17\right)-199.\left(-17+5\right)\)
\(=199.\left(-2\right)-199.\left(-12\right)\)
\(=199.\left(-2\right)+199.12\)
\(=199.\left(-2+12\right)\)
\(=199.10\)
\(=1990\)
8/ \(-39.\left(5-99\right)+99.\left(10-39\right)\)
\(=-39.5-39.\left(-99\right)+99.10+99.\left(-39\right)\)
\(=-39.\left(-99+99\right)-39.5+99.10\)
\(=0-195+990\)
\(=795\)
9/ \(-38.\left(25-4\right)+25.\left(-4+38\right)\)
\(=-38.25-38.\left(-4\right)+25.\left(-4\right)+25.38\)
\(=25.\left(-38+38\right)-4.\left(-38+25\right)\)
\(=0-4.\left(-13\right)\)
\(=52\)
10/ \(\left(-37\right).86+37.76\)
\(=37.\left(-86\right)+37.76\)
\(=37.\left(-86+76\right)\)
\(=37.\left(-10\right)\)
\(=-370\)
T
2
NA
28 tháng 1 2022
b, ( cái (99) là -99 hay +99)
\(c,=\left[\left(-25\right).\left(-4\right)\right].\left[9.\left(-7\right)\right]\\ =100.\left(-63\right)=-6300\\ d,=37.\left(-84\right)+37.\left(-16\right)\\ =37.\left[\left(-84\right)+\left(-16\right)\right]\\ =37.\left(-100\right)=-3700\)
28 tháng 1 2022
b) (-2).29+(-2).(99)+(-2).(-30)
=1.(-2).29+(-2).(99)+(-2)
=-2. (1+99+30)
=-2.130
=-260
c)(-25).9.(-4).(-7)
=[-25.(-4)].[9.(-7)]
=100.(-63)
=-6300
d) (-37).84+37.(-16)
=(-37+37).[84+(-16)]
=0.[84+(-16)]
=0
NA
5
24 tháng 11 2017
9.(x+1)=99
x+1=99:9
x+1=11
x =11-1
x=10
[(6:x-72):2-84]=5628
(6:x-72):2 =5628+84
(6:x-72):2 =5712
6:x-72 =5712.2
6:x-72 =11424
6:x =11424+72
6: x =11496
x =6:1496
x = 1/1916
13 tháng 11 2023
a: \(A=2^{100}-2^{99}+2^{98}-2^{97}+...+2^2-2\)
=>\(2A=2^{101}-2^{100}+2^{99}-2^{98}+...+2^3-2^2\)
=>\(2A+A=2^{101}-2^{100}+2^{99}-2^{98}+...+2^3-2^2+2^{100}-2^{99}+...+2^2-2\)
=>\(3A=2^{101}-2\)
=>\(A=\dfrac{2^{101}-2}{3}\)
b: Sửa đề: \(A=\dfrac{2\cdot8^4\cdot27^2+4\cdot6^9}{2^7\cdot6^7+2^7\cdot40\cdot9^4}\)
\(A=\dfrac{2\cdot2^{12}\cdot3^6+2^2\cdot2^9\cdot3^9}{2^7\cdot2^7\cdot3^7+2^7\cdot2^3\cdot5\cdot3^8}\)
\(=\dfrac{2^{11}\cdot3^6\left(2^3+3^3\right)}{2^{10}\cdot3^7\left(2^4+5\cdot3\right)}\)
\(=\dfrac{2}{3}\cdot\dfrac{4+27}{16+15}=\dfrac{2}{3}\)
c: \(B=\dfrac{4^5\cdot9^4-2\cdot6^4}{2^{10}\cdot3^8+6^8\cdot20}\)
\(=\dfrac{2^{10}\cdot3^8-2\cdot2^4\cdot3^4}{2^{10}\cdot3^8+2^8\cdot2^2\cdot5\cdot3^8}\)
\(=\dfrac{2^5\cdot3^4\left(2^5\cdot3^4-1\right)}{2^{10}\cdot3^8\left(1+5\right)}=\dfrac{1}{2^5\cdot3^4}\cdot\dfrac{32\cdot81-1}{6}\)
\(=\dfrac{2591}{2^6\cdot3^5}\)
13 tháng 9 2020
a) 125 - 5(x + 10) = 12
=> 5(x + 10) = 125 - 12 = 113
=> x + 10 = 113 : 5
=> x + 10 = 113/5
=> x = 113/5 - 10 = 63/5
b) (x - 1)2 = 4 => (x - 1)2 = (\(\pm\)2)2
=> x - 1 = 2 hoặc x - 1 = -2
=> x = 3 hoặc x = -1
c) 5x+1 - 52 . 17 = 52.8
=> 5x . 5 - 52 . 17 = 52 . 8
=> 5x . 5 = 52.8 + 52 . 17
=> 5x . 5 = 52(8 + 17)
=> 5x . 5 = 52 . 52
=> 5x = \(\frac{5^2\cdot5^2}{5}=5^3\)
=> x = 3
d) 84 + (12 - 3.x) : 6 = 85
=> 84 + (12 - 3.x) = 510
=> 12 - 3.x = 426
=> 3.x = -414
=> x = -138
e) (x + 1) + (x + 2) + (x + 3) + ... + (x + 99) + (x + 100) = 5150
=> x + 1 + x + 2 + x + 3 + ... + x + 99 + x + 100 = 5150
=> (x + x + .... + x) + (1 + 2 + 3+ ... + 100) = 5150
=> 100x + 5050 = 5150
=> 100x = 5150 - 5050 = 100
=> x = 1
13 tháng 9 2020
Bài làm:
\(a,125-5.\left(x+10\right)=12\)
\(\Rightarrow5.\left(x+10\right)=125-12\)
\(\Rightarrow5.\left(x+10\right)=113\)
\(\Rightarrow x+10=\frac{113}{5}\)
\(\Rightarrow x=\frac{63}{5}\)
\(b,\left(x-1\right)^2=4\)
\(\Rightarrow\left(x-1\right)^2=2^2\)
\(\Rightarrow\orbr{\begin{cases}x-1=2\\x-1=-2\end{cases}}\Rightarrow\orbr{\begin{cases}x=3\\x=-1\end{cases}}\)
\(c,5^{x+1}-5^2.17=5^2.8\)
\(\Rightarrow5^{x+1}-425=200\)
\(\Rightarrow5^{x+1}=200+425\)
\(\Rightarrow5^{x+1}=625\)
\(\Rightarrow5^{x+1}=5^4\)
\(\Rightarrow x+1=4\)
\(\Rightarrow x=3\)
\(d,84+\left(12-3.x\right):6=85\)
\(\left(12-3x\right):6=85-84\)
\(\left(12-3x\right):6=1\)
\(12-3x=6\)
\(3x=6\)
\(x=2\)
\(e,\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+99\right)+\left(x+100\right)=5150\)
\(100.x+\left(1+2+3+...+99+100\right)=5150\)
\(100.x+5050=5150\)
\(100.x=5150-5050\)
\(100.x=100\)
\(x=1\)
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