Rut gon phan thuc :
a2 + ac - b2 - bc/ a2 - b2
Tinh :
x-y/ xy+y2 - 3x+y/x2 - xy . y-x/x+y
may dau gach cheo la nhu kieu phan so nhe, dau cham la dau nhan. Cac ban giup minh voiiii !
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\(\frac{7.9+14.27+21.36}{21.27+42.81+63.108}=\frac{7.3^2+2.7.3^3+3.7.2^2.3^2}{3.7.3^3+2.3.7.3^4+7.3^2.2^2.3^3}=\frac{7.3^2+2.7.3^3+3^3.7.2^2}{3^4.7+2.7.3^5+2^2.7.3^5}\)\(=\frac{7.3^2\left(1+2.3+2^2.3\right)}{3^4.7\left(1+2.3+2^2.3\right)}=\frac{7.3^2}{3^4.7}=\frac{1}{3^2}=\frac{1}{9}\)
\(S=\dfrac{1}{3.5}+\dfrac{1}{5.7}+\dfrac{1}{7.9}+...+\dfrac{1}{97.99}\)
\(2S=\dfrac{2}{3.5}+\dfrac{2}{5.7}+\dfrac{2}{7.9}+...+\dfrac{2}{97.99}\)
\(2S=\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+...+\dfrac{1}{97}-\dfrac{1}{99}\)
\(2S=\dfrac{1}{3}-\dfrac{1}{99}\)
\(2S=\dfrac{32}{99}\)
\(S=\dfrac{32}{99}:2\)
\(S=\dfrac{16}{99}\)
Cảm ơn bạn rất nhiều! Bạn đã cứu mình rùi! Xin trân thành cảm ơn!
\(x=4:\frac{52}{91}=7\)
\(y=21.\frac{52}{91}=12\)
\(z=49.\frac{52}{91}=28\)
Theo đề bài ta có : \(\frac{7}{x}\) = \(\frac{y}{27}\)= \(\frac{-7}{9}\)
Ta có:
+ \(\frac{7}{x}\)= \(\frac{-7}{9}\)
=> 7 . 9 = -7 . x => x = \(\frac{7.9}{-7}\)= -9
+ \(\frac{y}{27}\)= \(\frac{-7}{9}\)
=> y . 9 = -7. 27 => y = \(\frac{-7.27}{9}\) = -21
Chúc bạn học tốt nhoa!!!🥰🥰🥰
Ta có : \(S=\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{97.99}\)
\(\Rightarrow2S=2\left(\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{97.99}\right)\)
\(\Rightarrow2S=\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{97.99}\)
\(\Rightarrow2S=\left(\frac{1}{3}-\frac{1}{5}\right)+\left(\frac{1}{5}-\frac{1}{7}\right)+...+\left(\frac{1}{97}-\frac{1}{99}\right)\)
\(\Rightarrow2S=\left(\frac{1}{3}-\frac{1}{99}\right)+\left[\left(\frac{1}{5}+...+\frac{1}{97}\right)-\left(\frac{1}{5}+\frac{1}{7}+...+\frac{1}{97}\right)\right]\)
\(\Rightarrow2S=\left(\frac{33}{99}-\frac{1}{99}\right)+0\)
\(\Rightarrow2S=\frac{32}{99}\)
\(\Rightarrow S=\frac{32}{99}\div2\)
\(\Rightarrow S=\frac{16}{99}\)
\(S=\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+...+\frac{1}{97.99}\)
\(S=\frac{1}{2}.\left(\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{97.99}\right)\)
\(S=\frac{1}{2}.\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{97}-\frac{1}{99}\right)\)
\(S=\frac{1}{2}.\left(\frac{1}{3}-\frac{1}{99}\right)\)
\(S=\frac{1}{2}.\frac{32}{99}=\frac{16}{99}\)
\(\frac{2x6x11}{33x24}\) = \(\frac{12x11}{33x24}\) = 12 x 11 / 333 x 242 = \(\frac{1}{6}\)