Tìm x
3x=26=6
x : 4 1 phần 3=2,5
3 phần 4 x=1 phần 2
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7/48 - (1/2 x 2 + 1/6 x 4 + 1/8 x 5 + 1/12 x 7 + 1/14 x 8) : x = 0
7/48 - (1 + 2/3 + 5/8 + 7/12 + 4/7) : x = 0 (đã rút gọn)
7/48 - (336/336 + 224/336 + 210/336 + 196/336 + 192/336) : x = 0 (quy đồng)
7/48 - 193/56 : x = 0
193/56 : x = 0 + 7/48
193/56 : x = 7/48
x = 193/56 : 7/48
x = 1158/49
a/ \(2x+\frac{1}{7}=\frac{1}{3}\)
=> \(2x=\frac{1}{3}-\frac{1}{7}=\frac{7}{21}-\frac{3}{21}\)
=> \(2x=\frac{4}{21}\)
=> \(x=\frac{4}{21}:2=\frac{4}{21}.\frac{1}{2}=\frac{2}{21}\)
b/ \(3\left(x-\frac{1}{2}\right)=\frac{4}{9}\)
=> \(x-\frac{1}{2}=\frac{4}{9}:3=\frac{4}{9}.\frac{1}{3}\)
=> \(x-\frac{1}{2}=\frac{4}{27}\)
=> \(x=\frac{4}{27}+\frac{1}{2}=\frac{8}{54}+\frac{27}{54}=\frac{35}{54}\)
c/ \(\left(x-5\right)^2+4=68\)
=> \(\left(x-5\right)^2=68-4=64\)
=> \(\left[{}\begin{matrix}x-5=8\\x-5=-8\end{matrix}\right.\)
=> \(\left[{}\begin{matrix}x=8+5=13\\x=-8+5=-3\end{matrix}\right.\)
d/ \(\left(\left|x\right|-\frac{1}{2}\right)\left(2x+\frac{3}{2}\right)=0\)
=> \(\left[{}\begin{matrix}\left|x\right|-\frac{1}{2}=0\\2x+\frac{3}{2}=0\end{matrix}\right.\)
=> \(\left[{}\begin{matrix}\left|x\right|=0+\frac{1}{2}=\frac{1}{2}\\2x=0-\frac{3}{2}=-\frac{3}{2}\end{matrix}\right.\)
=> \(\left[{}\begin{matrix}\left[{}\begin{matrix}x=\frac{1}{2}\\x=-\frac{1}{2}\end{matrix}\right.\\x=-\frac{3}{2}:2=-\frac{3}{2}.\frac{1}{2}=-\frac{3}{4}\end{matrix}\right.\)
e) \(5x+2=3x+8\)
=> \(5x-3x=8-2=6\)
=> \(2x=6\)
=> \(x=6:2=3\)
f/ \(26-\left(5-2x\right)=27\)
=> \(5-2x=26-27=-1\)
=> \(2x=5-\left(-1\right)=5+1=6\)
=> \(x=6:2=3\)
g/ \(\left(4x-8\right)-\left(2x-6\right)=4\)
=> \(4x-8-2x+6=4\)
=> \(\left(4x-2x\right)+\left(-8+6\right)=4\)
=> \(2x+-2=4\)
=> \(2x=4+2=6\)
=> \(x=6:2=3\)
h/ \(\left(x+3\right)^3:3-1=-10\)
=> \(\left(x+3\right)^3:3=-10+1=-9\)
=> \(\left(x+3\right)^3=-9.3=-27\)
=> \(x+3=-3\)
=> \(x=-3-3=-6\)
Giải:
2 / 1/ 2x-1 / 3 / -3 / 2 =1/4
⇔2:1:2x-1:3:-3:2=1/4
2:2x-1:-1:2=1/4
2:2x-1:-1/2=1/4
2:2x-1 =1/4.-1/2
2:2x-1 =-1/8
2x-1 =2:-1/8
2x-1 =-16
2x =-16+1
2x =-15
x =-15:2
x =-15/2
Chúc bạn học tốt!
a, \(x\)<\(\frac{3}{4}\)+\(\frac{4}{3}\) <=> \(x\)<\(\frac{25}{12}\)vì x là số tự nhiên => x = 2:x = 1
b,\(\frac{1}{2}\)x\(\frac{1}{3}\)<\(x\)< \(\frac{1}{4}\): \(\frac{1}{8}\)<=> \(\frac{1}{6}\)< x < 2 vì x là số tự nhiên => x = 1 .
Chúc bạn học toots~<>
đề như z ak bn!
a)* 3x =26
=> x = 26/3
* 3x = 6
=> x = 2
b) \(x:4\times\frac{1}{3}=2,5\)
\(x\times\frac{1}{4}\times\frac{1}{3}=2,5\)
\(x\times\frac{1}{12}=2,5\)
\(x=2,5:\frac{1}{12}\)
\(x=30\)
c) \(\frac{3}{4x}=\frac{1}{2}=\frac{3}{6}\)
\(\Rightarrow\frac{3}{4x}=\frac{3}{6}\)
\(\Rightarrow4x=6\)
\(x=6:4\)
\(x=\frac{3}{2}\)
nếu như đề mk viết sai thì nhắn lại cho mk, mk sửa nha!
x=1,5 bạn nhé