Question

[Thuy Duong Nguyen]

a, ( -1/2 x³ y)² . 2xy .(-xy)²

b, ( 1/3 x³y) . (xy²)².3/2x²

bạn nào siêu toán 7 giúp tớ với 😶😶😶

mình tích cho cái 

Answer 1

[Huỳnh Phước Mạnh]

a) \(\left(-\frac{1}{2}x^3y\right)^2\cdot2xy\cdot\left(-xy\right)^2=\left(-\frac{1}{2}\right)^2x^6y^2\cdot2xy\cdot\left(-1\right)^2x^2y^2\)

                                                      \(=\frac{1}{4}x^6y^2\cdot2xy\cdot x^2y^2=\left(\frac{1}{4}\cdot2\right)x^6x\cdot x^2\cdot y^2\cdot y\cdot y^2=\frac{1}{2}x^9y^5\)

b) \(\left(\frac{1}{3}x^3y\right)\left(xy^2\right)^2\cdot\frac{3}{2}x^2=\frac{1}{3}x^3y\cdot x^2y^4\cdot\frac{3}{2}x^2\)

\(=\left(\frac{1}{3}\cdot\frac{3}{2}\right)x^3\cdot x^2\cdot x^2\cdot y\cdot y^4=\frac{1}{2}x^7y^5\)

\(=\frac{1}{4}x^6y^2\cdot2xy\cdot x^2y^2=\left(\frac{1}{4}\cdot2\right)x^6x\cdot x^2\cdot y^2\cdot y\cdot y^2=\frac{1}{2}x^9y^5\)