tính hợp lí
-7^5. 3^3 / 7^2. (-3)^3
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\(-\dfrac{2}{5}.\dfrac{4}{7}+\dfrac{-3}{5}.\dfrac{2}{7}+\dfrac{-3}{5}\)
= \(\dfrac{-8}{35}+\dfrac{-6}{35}+\dfrac{-3}{5}\)
=\(\dfrac{-8-6-21}{35}\)
=\(\dfrac{-35}{35}\)
=-1
`(-2)/5.4/7+(-3)/5.2/7+(-3)/5`
`=(-8)/3 +(-6)/35+(-3)/5`
`=(-8)-6-21/35`
`=(-35)/35`
`=(-1)`
`@Nae`
(1/2-2/3)-(5/3-3/2)+(7/3-5/2)
=1/2-2/3-5/3+3/2+7/3-5/2
=(1/2+3/2-5/2)-(2/3+5/3-7/3)
=-1/2-0=-1/2
\(#N\)
\(-\dfrac{11}{7}+\dfrac{13}{-2}+-\dfrac{6}{17}=-\dfrac{113}{14}+-\dfrac{6}{17}=-\dfrac{2005}{238}\)
\(\dfrac{13}{-8}+-\dfrac{7}{20}+\dfrac{3}{-8}=\left(-\dfrac{13}{8}+-\dfrac{3}{8}\right)+-\dfrac{7}{20}=-2+-\dfrac{7}{20}=-\dfrac{47}{20}\)
\(-\dfrac{4}{7}+\dfrac{11}{5}+\dfrac{1}{5}+-\dfrac{7}{3}=-\dfrac{4}{7}+\left(\dfrac{11}{5}+\dfrac{1}{5}\right)+-\dfrac{7}{3}=-\dfrac{4}{7}+\dfrac{12}{5}+-\dfrac{7}{3}=-\dfrac{53}{105}\)
\(a,-\frac{4}{7}+\left(-\frac{2}{3}+\frac{3}{7}\right)=-\frac{4}{7}-\frac{2}{3}+\frac{3}{7}=-\frac{4}{7}+\frac{3}{7}-\frac{2}{3}=-\frac{1}{7}-\frac{2}{3}=-\frac{17}{21}\)
\(b,-\frac{3}{10}\cdot\frac{5}{12}+-\frac{3}{10}\cdot\frac{7}{12}+5\cdot\frac{3}{10}=\frac{3}{10}\cdot-\frac{5}{12}+\frac{3}{10}\cdot-\frac{7}{12}+5\cdot\frac{3}{10}=\frac{3}{10}\cdot\left(-\frac{5}{12}-\frac{7}{12}+5\right)\)
\(=\frac{3}{10}\cdot4=\frac{6}{5}\)
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(2/5 + 2/7 - 2/11) : (3/7 - 3/11 + 3/5)
= 194/385 : 291/385
= 194/385 . 385/291
= 2/3
\(=\dfrac{-3}{5}:\dfrac{7}{5}-\dfrac{3}{5}:\dfrac{7}{5}+2\dfrac{3}{5}\)
\(=-\dfrac{6}{5}\times\dfrac{5}{7}+\dfrac{13}{5}=\dfrac{61}{35}\)
\(\left(\dfrac{1}{3}-\dfrac{3}{10}\right):\dfrac{3}{5}+\left(\dfrac{2}{3}-\dfrac{7}{10}\right):\dfrac{3}{5}\)
\(=\left(\dfrac{1.10}{3.10}-\dfrac{3.3}{10.3}\right).\dfrac{5}{3}+\left(\dfrac{2.10}{3.10}-\dfrac{7.3}{10.3}\right).\dfrac{5}{3}\)
\(=\left(\dfrac{10}{30}-\dfrac{9}{30}\right).\dfrac{5}{3}+\left(\dfrac{20}{30}-\dfrac{21}{30}\right).\dfrac{5}{3}\)
\(=\dfrac{1}{30}.\dfrac{5}{3}-\dfrac{1}{30}.\dfrac{5}{3}\)
\(=\dfrac{5}{3}.\left(\dfrac{1}{30}-\dfrac{1}{30}\right)\)
\(=\dfrac{5}{3}.0\)
\(=0\)
bài 1.tính bằng cách hợp lí nhất :
a) 1/7 + 2/7 + 3/7 + ..... 3 5/7 + 3 6/7
b) 3/5x 3 5/9 + 6/5 x 11/9
\(\frac{-4}{7}+\left(\frac{-2}{3}+\frac{4}{7}\right)\)
\(=\frac{-4}{7}+\frac{-2}{3}+\frac{4}{7}\)
\(=\left(\frac{-4}{7}+\frac{4}{7}\right)+\frac{-2}{3}\)
\(=0+\frac{-2}{3}=\frac{-2}{3}\)
~ Hok tốt ~
\(\frac{-3}{10}.\frac{5}{12}+\frac{-3}{10}.\frac{7}{12}+5\frac{3}{10}\)
\(=\frac{-3}{10}.\frac{5}{12}+\frac{-3}{10}.\frac{7}{12}+\frac{53}{10}\)
\(=\frac{-3}{10}.\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{53}{10}\)
\(=\frac{-3}{10}.1+\frac{53}{10}\)
\(=\frac{-3}{10}+\frac{53}{10}=\frac{50}{10}=5\)
~ Hok tốt ~
\(\frac{-7^5\times3^3}{7^2\times\left(-3\right)^3}\)\(=\frac{7^5\times3^3}{7^2\times3^3}\)\(=\frac{7^5}{7^2}\)\(=7^3=343\)
-7^5×3^3/7^2×3^3
= -7^3×7^2×3^3/7^2×3^3
=)-7^3