Tìm x :a) \(\frac{2}{3}\)x - \(\frac{3}{2}\)x = \(\frac{5}{12}\)b) \(\frac{2}{5}\) \(\frac{3}{5}\). (3x - 3,7) = -\(\frac{53}{10}\)c) \(\frac{7}{9}\): (2 \(\frac{3}{4}\)x) \(\frac{5}{9}\)=\(\frac{...

NN

Nguyễn Nhật Giang

1 tháng 5 2018 - olm

Tìm x :a) \(\frac{2}{3}\)x - \(\frac{3}{2}\)x = \(\frac{5}{12}\)b) \(\frac{2}{5}\)+\(\frac{3}{5}\). (3x - 3,7) = -\(\frac{53}{10}\)c) \(\frac{7}{9}\): (2 + \(\frac{3}{4}\)x) + \(\frac{5}{9}\)=\(\frac{23}{27}\)d) l 2x - \(\frac{1}{3}\)l + \(\frac{5}{6}\)=...

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#Toán lớp 6

4

LC

Lê Cao Mai Anh

1 tháng 5 2018

a, \(\frac{2}{3}x-\frac{3}{2}x=\frac{5}{12}\)

\(\left(\frac{2}{3}-\frac{3}{2}\right)x=\frac{5}{12}\)

\(\frac{-5}{6}x=\frac{5}{12}\)

x = \(\frac{-1}{2}\)

Vậy x = \(\frac{-1}{2}\)

~~~
#Sunrise

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D

dungnguyen

1 tháng 5 2018

a)2/3x-3/2x=5/12

x(2/3-3/2)=5/12

x(-5/6)=5/12

x=5/12/(-5/6)

x=-1/2

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M

Mavis

12 tháng 4 2017 - olm

a) \(\frac{2}{3}.x-\frac{3}{2}.x=\frac{5}{12}\)

b) \(\frac{2}{5}+\frac{3}{5}.\left(3x-3,7\right)=-\frac{53}{10}\)

c) \(\frac{7}{9}:\left(2+\frac{3}{4}.x\right)+\frac{5}{9}=\frac{23}{27}\)

#Toán lớp 6

2

HT

Hoàng Tử Rồng 1411

12 tháng 4 2017

a) 2/3*x-3/2*x=5/12

x*(2/3-3/2)=5/12

x*(-5/6)=5/12

x=5/12:(-5/6)

x=-1/2

b)2/5+3/5*(3x-3,7)=-53/10

3/5*(3x-3,7)=(-53/10)-2/5=-57/10

(3x-3,7)=(-57/10):3/5=-19/2

3x=(-19/2)+3,7

3x=-29/5

x=(-29/5):3=-29/15

c) 7/9:(2+3/4*x)+5/9=23/27

7/9:(2+3/4*x)=8/27

2+3/4*x=21/8

3/4*x=5/8

x=5/6

k mình nha

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HT

hoàng thi kim diệu

12 tháng 4 2017

a) 2/3.x-3/2.x=5/12

x.(2/3-3/2) =5/12

x.-5/6 =5/12

x =5/12:-5/6

x =1/2

b)2/5+3/5.(3x-3,7)=-53/10

3/5.(3x-3,7)=-53/10-2/5

3/5.(3x-3,7)=-57/10

3x-3,7 =-57/10:3/5

3x-3,7 =-19/2

3x =--19/2+3,7

3x =-29/5

x =-29/5:3

x =29/15

c)7/9:(2+3/4.x)+5/9=23/27

7/9:(2+3/4.x) =23/27-5/9

7/9:(2+3/4.x) =28/27

2+3/4.x =7/9:28/27

2+3/4.x =3/4

3/4.x =3/4-2

3/4.x =-5/4

x =-5/4:3/4

x =-5/3

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AJ

agelina jolie

30 tháng 5 2016

tìm số x , biết...

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#Toán lớp 6

7

PA

Phương An

30 tháng 5 2016

a.

\(\frac{2}{3}x-\frac{3}{2}x=\frac{5}{12}\)

\(\left(\frac{2}{3}-\frac{3}{2}\right)\times x=\frac{5}{2}\)

\(\left(\frac{4-9}{6}\right)\times x=\frac{5}{2}\)

\(-\frac{5}{6}\times x=\frac{5}{2}\)

\(x=\frac{5}{2}\div\left(-\frac{5}{6}\right)\)

\(x=\frac{5}{2}\times\left(-\frac{6}{5}\right)\)

\(x=-3\)

b.

\(\frac{2}{5}+\frac{3}{5}\times\left(3x-3,7\right)=-\frac{53}{10}\)

\(\frac{3}{5}\times\left(3x-3,7\right)=-\frac{53}{10}-\frac{2}{5}\)

\(\frac{3}{5}\times\left(3x-3,7\right)=\frac{-53-4}{10}\)

\(\frac{3}{5}\times\left(3x-3,7\right)=-\frac{57}{10}\)

\(3x-3,7=-\frac{57}{10}\div\frac{3}{5}\)

\(3x-3,7=-\frac{57}{10}\times\frac{5}{3}\)

\(3x-\frac{37}{10}=-\frac{19}{2}\)

\(3x=-\frac{19}{2}+\frac{37}{10}\)

\(3x=\frac{-95+37}{10}\)

\(3x=-\frac{58}{10}\)

\(3x=-\frac{29}{5}\)

\(x=-\frac{29}{5}\div3\)

\(x=-\frac{29}{5}\times\frac{1}{3}\)

\(x=-\frac{29}{15}\)

c.

\(\frac{7}{9}\div\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)

\(\frac{7}{9}\div\left(2+\frac{3}{4}x\right)=\frac{23}{27}-\frac{5}{9}\)

\(\frac{7}{9}\div\left(2+\frac{3}{4}x\right)=\frac{23-15}{27}\)

\(\frac{7}{9}\div\left(2+\frac{3}{4}x\right)=\frac{8}{27}\)

\(2+\frac{3}{4}x=\frac{7}{9}\div\frac{8}{27}\)

\(2+\frac{3}{4}x=\frac{7}{9}\times\frac{27}{8}\)

\(2+\frac{3}{4}x=\frac{21}{8}\)

\(\frac{3}{4}x=\frac{21}{8}-2\)

\(\frac{3}{4}x=\frac{21-16}{8}\)

\(\frac{3}{4}x=\frac{5}{8}\)

\(x=\frac{5}{8}\div\frac{3}{4}\)

\(x=\frac{5}{8}\times\frac{4}{3}\)

\(x=\frac{5}{6}\)

d.

\(-\frac{2}{3}\times x+\frac{1}{5}=\frac{3}{10}\)

\(-\frac{2}{3}\times x=\frac{3}{10}-\frac{1}{5}\)

\(-\frac{2}{3}\times x=\frac{3-2}{10}\)

\(-\frac{2}{3}\times x=\frac{1}{10}\)

\(x=\frac{1}{10}\div\left(-\frac{2}{3}\right)\)

\(x=\frac{1}{10}\times\left(-\frac{3}{2}\right)\)

\(x=-\frac{3}{20}\)

e.

\(\left|x\right|-\frac{3}{4}=\frac{5}{3}\)

\(\left|x\right|=\frac{5}{3}+\frac{3}{4}\)

\(\left|x\right|=\frac{20+9}{12}\)

\(\left|x\right|=\frac{29}{12}\)

\(x=\pm\frac{29}{12}\)

Vậy \(x=\frac{29}{12}\) hoặc \(x=-\frac{29}{12}\)

f.

\(\left|2x-\frac{1}{3}\right|+\frac{5}{6}=1\)

\(\left|2x-\frac{1}{3}\right|=1-\frac{5}{6}\)

\(\left|2x-\frac{1}{3}\right|=\frac{6-5}{6}\)

\(\left|2x-\frac{1}{3}\right|=\frac{1}{6}\)

\(2x-\frac{1}{3}=\pm\frac{1}{6}\)

\(2x-\frac{1}{3}=\frac{1}{6}\)

\(2x=\frac{1}{6}+\frac{1}{3}\)

\(2x=\frac{1+2}{6}\)

\(2x=\frac{3}{6}\)

\(2x=\frac{1}{2}\)

\(x=\frac{1}{2}\div2\)

\(x=\frac{1}{2}\times\frac{1}{2}\)

\(x=\frac{1}{4}\)

\(2x-\frac{1}{3}=-\frac{1}{6}\)

\(2x=-\frac{1}{6}+\frac{1}{3}\)

\(2x=\frac{-1+2}{6}\)

\(2x=\frac{1}{6}\)

\(x=\frac{1}{6}\div2\)

\(x=\frac{1}{6}\times\frac{1}{2}\)

\(x=\frac{1}{12}\)

Vậy x = 1/4 hoặc x = 1/12.

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PA

Phương An

30 tháng 5 2016

Sorry nha, mik chép lộn đềLàm lại câu a nha

a.

\(\frac{2}{3}x-\frac{3}{2}x=\frac{5}{12}\)

\(\left(\frac{2}{3}-\frac{3}{2}\right)\times x=\frac{5}{12}\)

\(\left(\frac{4-9}{6}\right)\times x=\frac{5}{12}\)

\(-\frac{5}{6}\times x=\frac{5}{12}\)

\(x=\frac{5}{12}\div\left(-\frac{5}{6}\right)\)

\(x=\frac{5}{12}\times\left(-\frac{6}{5}\right)\)

\(x=-\frac{1}{2}\)

Chúc bạn học tốt

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DN

Dương Nguyễn Khánh Huyền

21 tháng 6 2016

Bài 1: tìm x:a)\(\frac{2}{3}\).x-\(\frac{3}{2}\).x=\(\frac{5}{12}\)b) \(\frac{7}{9}\):(2+\(\frac{3}{4}\).x)+\(\frac{5}{9}\)=\(\frac{23}{27}\)c)\(\frac{2}{5}\)+\(\frac{3}{5}\).(3x-3,7)=...

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#Toán lớp 6

8

DT

Đinh Tuấn Việt

21 tháng 6 2016

a) \(x.\left(\frac{2}{3}-\frac{3}{2}\right)=\frac{5}{12}\)

\(\Leftrightarrow x.\left(-\frac{5}{6}\right)=\frac{5}{12}\)

\(\Leftrightarrow x=-\frac{1}{2}\)

b) \(\frac{7}{9}:\left(2+\frac{3}{4}x\right)=\frac{8}{27}\)

\(\Leftrightarrow2+\frac{3}{4}x=\frac{21}{8}\)

\(\Leftrightarrow\frac{3}{4}x=\frac{5}{8}\)

\(\Leftrightarrow x=\frac{5}{6}\)

c) \(\frac{3}{5}.\left(3x-3,7\right)=-\frac{57}{10}\)

\(\Leftrightarrow3x-3,7=-\frac{19}{2}\)

\(\Leftrightarrow3x=-\frac{29}{5}\)

\(\Leftrightarrow x=-\frac{29}{15}\)

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PA

Phương An

21 tháng 6 2016

Toán lớp 6

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HA

Hoàng Anh Thu

29 tháng 4 2018 - olm

bài 2 tìm...

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#Toán lớp 6

0

NB

Nguyễn Bảo Nhi

19 tháng 4 2019 - olm

...

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#Toán lớp 6

8

NB

Nguyễn Bảo Nhi

19 tháng 4 2019

Câu a \(\left|2x-\frac{1}{3}\right|+\frac{5}{6}=1\)

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KN

Kiệt Nguyễn

19 tháng 4 2019

g) \(\left(x+\frac{1}{2}\right)\left(\frac{2}{3}-2x\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x+\frac{1}{2}=0\\\frac{2}{3}-2x=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{-1}{2}\\x=\frac{1}{3}\end{cases}}\)

Vây \(x\in\left\{\frac{-1}{2};\frac{1}{3}\right\}\)

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F

Fenny

10 tháng 6 2020 - olm

Tim x biet

a) \(\frac{2}{3}x+\frac{5}{6}x+\frac{1}{2}=\frac{-3}{4}\)

b) \(\frac{2}{5}+\frac{3}{5}.\left(3x-3,7\right)=-\frac{53}{10}\)

#Toán lớp 6

3

KA

Kiyotaka Ayanokoji

10 tháng 6 2020

a, \(\frac{2}{3}x+\frac{5}{6}x+\frac{1}{2}=\frac{-3}{4}\)

\(\Leftrightarrow\frac{3}{2}x=\frac{-5}{4}\)

\(\Leftrightarrow x=\frac{-5}{6}\)

b, \(\frac{2}{5}+\frac{3}{5}.\left(3x-3,7\right)=\frac{-53}{10}\)

\(\Leftrightarrow\frac{3}{5}.\left(3x-\frac{37}{10}\right)=\frac{-57}{10}\)

\(\Leftrightarrow3x-\frac{37}{10}=\frac{-19}{2}\)

\(\Leftrightarrow3x=\frac{-29}{5}\)

\(\Leftrightarrow x=\frac{-29}{15}\)

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LD

l҉o҉n҉g҉ d҉z҉

10 tháng 6 2020

a) \(\frac{2}{3}x+\frac{5}{6}x+\frac{1}{2}=-\frac{3}{4}\)

\(x\left(\frac{2}{3}+\frac{5}{6}\right)+\frac{1}{2}=-\frac{3}{4}\)

\(x\cdot\frac{3}{2}=\frac{-5}{4}\)

\(x=-\frac{5}{6}\)

\(\frac{2}{5}+\frac{3}{5}\left(3x-3,7\right)=-\frac{53}{10}\)

\(\frac{3}{5}\left(3x-\frac{37}{10}\right)=-\frac{57}{10}\)

\(3x-\frac{37}{10}=-\frac{19}{2}\)

\(3x=\frac{-29}{5}\)

\(x=\frac{-29}{15}\)

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H2

Hiếu 2k6

5 tháng 3 2020 - olm

Ai giúp vs !!!
\(a.\frac{3x-7}{5}=\frac{2x-1}{3}\\ b.\frac{4x-7}{12}-x=\frac{3x}{8}\\ c.\frac{x-2009}{1234}+\frac{x-2009}{5678}-\frac{x-2009}{197}=0\\ d.\frac{5x-8}{3}=\frac{1-3x}{2}\\ e.\frac{x-5}{6}-\frac{x-9}{4}=\frac{5x-3}{8}+2\\ f.\frac{x-1}{\frac{2}{5}}-3-\frac{3x-2}{\frac{5}{4}}-2=1\)

#Toán lớp 8

8