so sánh S với 1/2 biết S = 2/3! + 3/4! + 4/5! + ... + 2016/2017!
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Ta có :
\(S=\frac{2}{3!}+\frac{3}{4!}+\frac{4}{5!}+...+\frac{2016}{2017!}\)
\(S=\frac{3-1}{3!}+\frac{4-1}{4!}+\frac{5-1}{5!}+...+\frac{2017-1}{2017!}\)
\(S=\frac{3}{3!}-\frac{1}{3!}+\frac{4}{4!}-\frac{1}{4!}+\frac{5}{5!}-\frac{1}{5!}+...+\frac{2017}{2017!}-\frac{1}{2017!}\)
\(S=\frac{1}{2!}-\frac{1}{3!}+\frac{1}{3!}-\frac{1}{4!}+\frac{1}{4!}-\frac{1}{5!}+...+\frac{1}{2016!}-\frac{1}{2017!}\)
\(S=\frac{1}{2!}-\frac{1}{2017!}\)
\(S=\frac{1}{2}-\frac{1}{2017!}\)
Vậy \(S=\frac{1}{2}-\frac{1}{2017!}\)
Chúc bạn học tốt ~
A=\(\dfrac{3}{1\cdot2\cdot3}+\dfrac{3}{2\cdot3\cdot4}+...+\dfrac{3}{2015\cdot2016\cdot2017}\)
Nhận xét:\(\dfrac{1}{\left(n-1\right)n}-\dfrac{1}{n\left(n+1\right)}=\dfrac{n+1-n+1}{\left(n-1\right)n\left(n+1\right)}=\dfrac{2}{\left(n-1\right)n\left(n+1\right)}\)
=>A=\(3\cdot\dfrac{1}{2}\cdot\left(\dfrac{1}{1\cdot2}-\dfrac{1}{2\cdot3}+\dfrac{1}{2\cdot3}-\dfrac{1}{3\cdot4}+...+\dfrac{1}{2015\cdot2016}-\dfrac{1}{2016\cdot2017}\right)=\dfrac{3}{2}\cdot\left(\dfrac{1}{2}-\dfrac{1}{2016\cdot2017}\right)=\dfrac{3}{4}-\dfrac{3}{2.2016.2017}< \dfrac{3}{4}< 1\)
Vậy A<1
Ta có : S = 1 +21+22+........+22017
2S= 2 +22+23+.......+22018
2S -S =( 2+22+23+......+22018) - (1+2+22+.......+22017)
S = 22018-1
S =22018- 1
S = 22 . 22016-1
\(\Rightarrow\)S < 5. 22016
Ta có :S= 1+ 2 + 22 + ........+ 22017
Suy ra 2S = 2 + 22 +.......+22018
Suy ra 2S -S = (2-2) + (22-22)+......+(22018 - 1)
Suy ra S=22018-1
S=1+5+5^2+...+5^2017
(=)S=(1+5+5^2)+...+(5^2015+5^2016+5^2017)
(=)S=1(1+5+5^2)+...+5^2015(1+5+5^2)
(=)S=1.31+...+5^2015.31
(=)S=(1+...+5^2015).31 chia het cho 31
Vay S chia het cho 31
3^3027 >4S
K MK NHE