Tính :
\(\frac{3}{2^2}+\frac{5}{6^2}+\frac{7}{12^2}+...+\frac{19}{90^2}\)
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\(\frac{5}{12}+\frac{5}{20}+\frac{5}{30}+...+\frac{5}{9900}=\frac{5}{3.4}+\frac{5}{4.5}+\frac{5}{5.6}+...+\frac{5}{99.100}\)
\(5\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{99}-\frac{1}{100}\right)\)
\(5\left(\frac{1}{3}-\frac{1}{100}\right)=\frac{97}{60}\)
a) \(74\frac{19}{35}.\frac{7}{90}+15\frac{16}{35}.\frac{7}{90}+2\frac{14}{90}\)
= \(\left(74\frac{19}{35}+15\frac{16}{35}\right).\frac{7}{90}+2\frac{14}{90}\)
= 90 . 7/90 + 194/90
= 630/90 + 194/90
= 824/90 = 412/45
b) (-2/5 + 3/7) - (4/9 + 12/20 - 13/35) + 7/35
= -2/5 + 3/7 - 4/9 - 3/5 + 13/35 + 7/35
= (-2/5 - 3/5) + 3/7 - 4/9 + (13/35 + 7/35)
= -1 + 3/7 - 4/9 + 4/7
= -1 + (3/7 + 4/7) - 4/9
= -1 + 1 - 4/9 = -4/9
\(\frac{3}{2^2}\)+\(\frac{5}{6^2}\)+\(\frac{7}{12^2}\)+ ....+\(\frac{19}{90^2}\)
= \(\frac{3}{4}\)+\(\frac{5}{36}\)+\(\frac{7}{144}\)+....+\(\frac{19}{8100}\)
= (\(\frac{3}{4}\)+\(\frac{5}{36}\)+\(\frac{7}{144}\)) + .... \(\frac{19}{8100}\)
= (\(\frac{108}{144}\)+\(\frac{20}{144}\)+\(\frac{7}{144}\)) +....+\(\frac{19}{8100}\)
= \(\frac{108+20+7}{144}\)+....+\(\frac{19}{8100}\)
=\(\frac{135}{144}\)+....+\(\frac{19}{8100}\)
=\(\frac{7593,75}{8100}\)+....+\(\frac{19}{8100}\)
=\(\frac{7593,75}{8100}\)+\(\frac{19}{8100}\)
=\(\frac{7593,75+19}{8100}\)
=\(\frac{7612,75}{8100}\)
mik không chắc đúng không?
=3/4+5/36+......+19/8100
=3/1.4+5/4.9+.............+19/81.100
=1/1-1/4+1/4-1/9+...............+1/81-1/90
=1/1-1/90=1-1/90=89/90