\(X^2\)\(\div\)\(\frac{16}{11}\)\(=\)\(\frac{11}{4}\)
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\(\frac{x+11}{12}+\frac{x+11}{13}+\frac{x+11}{14}=\frac{x+11}{15}+\frac{x+11}{16}\)
\(\Rightarrow\frac{x+11}{12}+\frac{x+11}{13}+\frac{x+11}{14}-\frac{x+11}{15}-\frac{x+11}{16}=0\)
\(\Rightarrow\left(x+11\right)\left(\frac{1}{12}+\frac{1}{13}+\frac{1}{14}-\frac{1}{15}-\frac{1}{16}\right)=0\)
Mà \(\left(\frac{1}{12}+\frac{1}{13}+\frac{1}{14}-\frac{1}{15}-\frac{1}{16}\right)\ne0\)
\(\Rightarrow x+11=0\Rightarrow x=-11\)
\(\left(4\frac{1}{2}-\frac{2}{5}x\right):\frac{7}{4}=\frac{11}{14}\)
\(\left(\frac{9}{2}-\frac{2}{5}x\right)=\frac{11}{14}.\frac{7}{4}=\frac{11}{8}\)
\(\frac{2}{5}x=\frac{9}{2}-\frac{11}{8}\)
\(\frac{2}{5}x=\frac{25}{8}\)
\(x=\frac{25}{8}.\frac{5}{2}=\frac{125}{16}\)
\(\left(4\frac{1}{2}-\frac{2}{5}x\right):\frac{7}{4}=\frac{11}{14}\)
\(\left(\frac{9}{2}-\frac{2}{5}x\right)=\frac{11}{14}x\frac{7}{4}\)
\(\left(\frac{9}{2}-\frac{2}{5}x\right)=\frac{11}{8}\)
\(\frac{2}{5}x=\frac{9}{12}-\frac{11}{8}\)
\(\frac{2}{5}x=\frac{-5}{8}\)
\(x=\frac{-5}{8}:\frac{2}{5}\)
\(x=\frac{-25}{16}\)
34 +14 :x=−2
\(\frac{1}{4}:x=-2-\frac{3}{4}\)
\(\frac{1}{4}:x=\frac{-11}{4}\)
\(x=\frac{1}{4}:\frac{-11}{4}\)
\(x=\frac{-1}{11}\)
x2:1611 =114
tìm x
\(\frac{3}{4}+\frac{1}{4}:x=-2\)
\(\frac{1}{4}:x=-2-\frac{3}{4}\)
\(\frac{1}{4}:x=\frac{-11}{4}\)
\(x=\frac{1}{4}:\frac{-11}{4}\)
\(x=\frac{-1}{11}\)
\(x^2:\frac{16}{11}=\frac{11}{4}\)
\(x^2=\frac{11}{4}\times\frac{16}{11}\)
\(x^2=4\)
\(\Rightarrow x=-2\)\(\text{hoặc}\)\(x=2\)
a= (\(\frac{2}{5}\)+\(\frac{2}{9}\)+\(\frac{2}{11}\)\(\times\)\(\frac{5}{7}\)\(+\frac{7}{9}\)\(+\frac{7}{11}\)\()\)
\(\frac{-1}{4}-\frac{3}{4}:x=\frac{-11}{36}\)
\(\frac{3}{4}:x=\frac{-1}{4}-\frac{-11}{36}\)
\(\frac{3}{4}:x=\frac{1}{18}\)
\(x=\frac{3}{4}:\frac{1}{18}\)
\(x=13,5\)
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\(x^2:\frac{16}{11}=\frac{11}{4}\)
\(x^2=\frac{16}{11}.\frac{11}{4}\)
\(x^2=4\)
\(=>x=2\)
\(x^2\)\(\div\)\(\frac{16}{11}\)=\(\frac{11}{4}\)
\(x^2\)= \(\frac{11}{4}\)\(\cdot\frac{16}{11}\)
\(x^2\)= 4
\(x^2\)=\(2^2\)
\(\Rightarrow\)\(x=2\)
Vậy \(x=2\)