\((\frac{15}{10}x+25)\div\frac{2}{3}=60\)
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TL
15 tháng 3 2019
\(x\times\frac{6}{25}=\frac{15}{-13}\)
x=\(\frac{15}{-13}\div\frac{6}{25}\)
x=\(-\frac{125}{26}\)
các câu còn lại làm tương tự nha!!!
KN
15 tháng 3 2019
\(1.x.\frac{6}{25}=\frac{15}{-13}\\ x=\frac{15}{-13}:\frac{6}{25}\\ x=-\frac{125}{26}\)
\(2.x:\frac{4}{10}=\frac{13}{-45}+\frac{8}{15}\\ x:\frac{4}{10}=\frac{11}{45}\\ x=\frac{11}{45}.\frac{4}{10}\\ x=\frac{22}{225}\)
\(3.\frac{3}{8}-\frac{1}{6}.x=\frac{1}{4}\\ \frac{1}{6}.x=\frac{3}{8}-\frac{1}{4}\\ \frac{1}{6}.x=\frac{1}{8}\\ x=\frac{1}{8}:\frac{1}{6}\\ x=\frac{3}{4}\)
\(4.\frac{1}{3}+\frac{1}{2}:x=-4\\ \frac{1}{2}:x=-4-\frac{1}{3}=-\frac{13}{3}\\ x=\frac{1}{2}:\left(-\frac{13}{3}\right)=-\frac{3}{26}\)
\(5.x+\frac{7}{12}=\frac{17}{18}-\frac{1}{9}=\frac{5}{6}\\ x=\frac{5}{6}-\frac{7}{12}\\ x=\frac{1}{4}\)
DD
21 tháng 1 2019
sai đề rồi nha...bạn thay dấu suy ra thành dấu tương đương giùm mik..mik bị nhầm
\(\frac{x+5}{65}+\frac{x+10}{60}=\frac{x+15}{35}+\frac{x+20}{50}\)
\(\Rightarrow\frac{x+5}{65}+\frac{x+10}{60}-\frac{x+15}{55}-\frac{x+20}{50}+2-2=0\)
\(\Rightarrow\left(\frac{x+5}{65}+1\right)+\left(\frac{x+10}{60}+1\right)-\left(\frac{x+15}{55}+1\right)-\left(\frac{x+20}{50}+1\right)=0\\ \)
\(\Rightarrow\left(\frac{x+5}{65}+\frac{65}{65}\right)+\left(\frac{x+10}{60}+\frac{60}{60}\right)-\left(\frac{x+15}{55}+\frac{55}{55}\right)-\left(\frac{x+20}{50}+\frac{50}{50}\right)=0\)
\(\Rightarrow\frac{x+70}{65}+\frac{x+70}{60}-\frac{x+70}{55}-\frac{x+70}{50}=0\)
\(\Rightarrow\left(x+70\right)\left(\frac{1}{65}+\frac{1}{60}-\frac{1}{55}-\frac{1}{50}\right)=0\)
\(\Rightarrow x+70=0\left(\frac{1}{65}+\frac{1}{60}-\frac{1}{55}-\frac{1}{50}\nè0\right)\)
\(\Leftrightarrow x=-70\)
học tốt...............nhớ k cho mik nha
28 tháng 7 2016
\(2\frac{2}{3}:\left\{\left[\left(3,72-0,02.x\right)\frac{10}{37}\right]:\frac{5}{6}+2,8\right\}-\frac{7}{15}=0,2\)
\(2\frac{2}{3}:\left\{\left[\left(3,75-0,02.x\right)\frac{10}{37}\right]:\frac{5}{6}+2,8\right\}=\frac{2}{3}\)
\(\left\{\left[\left(3,72-0,02.x\right)\frac{10}{37}\right]:\frac{5}{6}+2,8\right\}=4\)
\(\left[\left(3,72-0,02.x\right)\frac{10}{37}\right]:\frac{5}{6}=\frac{6}{5}\)
\(\left[\left(3,72-0,02.x\right)\frac{10}{37}\right]=1\)
\(\left(3,72-0,02.x\right)=\frac{37}{10}\)
\(0,02.x=0,02\)
\(x=1\)
28 tháng 7 2016
\(2\frac{2}{3}:\left\{\left[\left(3,72-0,02.x\right)\frac{10}{37}\right]:\frac{5}{6}+2,8\right\}-\frac{7}{15}=0,2\)
\(\Rightarrow\frac{8}{3}:\left\{\left[\left(\frac{93}{25}-\frac{1}{50}.x\right)\frac{10}{37}\right]:\frac{5}{6}+\frac{14}{5}\right\}-\frac{7}{15}=\frac{1}{5}\)
\(\Rightarrow\left\{\left[\frac{93}{25}-\frac{1}{50}.x\right]:\frac{5}{6}+\frac{14}{5}\right\}-\frac{7}{15}=\frac{8}{3}:\frac{1}{5}=\frac{40}{3}\)
\(\Rightarrow\left[\frac{93}{25}-\frac{1}{50}.x\right]:\frac{5}{6}+\frac{14}{5}=\frac{40}{3}+\frac{7}{15}=\frac{69}{5}\)
\(\Rightarrow\left[\frac{93}{25}-\frac{1}{50}.x\right]:\frac{5}{6}=\frac{69}{5}-\frac{14}{5}=11\)
\(\Rightarrow\frac{93}{25}-\frac{1}{50}.x=11.\frac{5}{6}=\frac{55}{6}\)
\(\Rightarrow\frac{1}{50}.x=\frac{93}{25}-\frac{55}{6}=\frac{-817}{150}\)
\(\Rightarrow x=\frac{-817}{150}:\frac{1}{50}=\frac{-817}{3}\)
Ủng hộ tớ nha m.n?
11 tháng 7 2019
1) ( \(\frac{55}{3}\): 15 + \(\frac{26}{3}\) . \(\frac{7}{2}\)) : [(\(\frac{37}{3}\) + \(\frac{62}{7}\)) . \(\frac{7}{18}\)] : \(\frac{-1704}{445}\)
= ( \(\frac{55}{3}\). \(\frac{1}{15}\) + \(\frac{91}{3}\)) : [ \(\frac{445}{21}\) . \(\frac{7}{18}\)] . \(\frac{-445}{1704}\)
= ( \(\frac{11}{9}\)+ \(\frac{91}{3}\)) : \(\frac{445}{54}\). \(\frac{-445}{1704}\) = \(\frac{284}{9}\). \(\frac{54}{445}\). \(\frac{-445}{1704}\)= \(\frac{284}{9}\). (\(\frac{54}{445}\). \(\frac{-445}{1704}\))
= \(\frac{284}{8}\). \(\frac{-9}{284}\)
= \(\frac{-9}{8}\)
AT
1 tháng 3 2017
Câu 6: \(\left|\dfrac{5}{6}x-10\right|\le0\)
mà \(\left|\dfrac{5}{6}x-10\right|\ge0\forall x\)
\(\Rightarrow\left|\dfrac{5}{6}x-10\right|=0\)
\(\Rightarrow\dfrac{5}{6}x-10=0\Rightarrow\dfrac{5}{6}x=10\)
\(\Rightarrow x=10:\dfrac{5}{6}=10.\dfrac{6}{5}=12\)
Vậy \(x=12\)
Câu 7:
\(2^{3x+2}=4^{x+5}\)
\(\Rightarrow2^{3x+2}=\left(2^2\right)^{x+5}\)
\(\Rightarrow2^{3x+2}=2^{2\left(x+5\right)}\)
\(\Rightarrow3x+2=2\left(x+5\right)\)
\(\Rightarrow3x+2=2x+10\)
\(\Rightarrow3x-2x=10-2\)
\(\Rightarrow x=8\)
Vậy \(x=8\)
=>15/10x+25=60.2/3
=>15/10x+25=40
=>15/10x=40-25
=>15/10x=15
=>x=15.10/15
=>x=10
vậy x=10
15/10x+25=40
15/10x=15
x=15:15/10
x=10