TÌM X
A) 2XA+6:3-B B)8:A-2+5XB
C)(A+B):5+7X3 C)8X2-(A+B):3
GIẢI GIÙM MÌNH NHA MẤY BẠN YÊU
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ta có a-b=c=>a=b+c
=>a+b+c=2a=150
=>a=150:2=75
=>b+c=75
=>c=(75+51):2(tổng -tỉ)
=>c=63
=>b=63-51=12
vậy a=75
b=12
c=63
Từ a-b=c -> c+b=a
=>a=b+c=150:2=75
b=(75-51):2=12
c=75-12=63
Đ/S:...
a. |x|+x=1/3 hoặc -x+x=1/3
=> x+x=1/3 hoặc 0=1/3(vô lí, loại)
=> 2x=1/3
=> x=1/3:2
=> x=1/3.1/2
=> x=1/6
b. |x|-x=3/4
=> x-x=3/4 hoặc -x-x=3/4
=> 0=3/4(vô lí, loại) hoặc -2x=3/4
=> x=3/4:(-2)
=> x=3/4.(-1/2)
=> x=-3/8
c. |x-3|=x
=> x-3=x hoặc -(x-3)=x
=> x-3-x=0 hoặc -x+3=x
=> -3=0(vô lí,loại) hoặc -x-x+3=0
=> -2x+3=0
=> -2x=-3
=> x=-3:(-2)
=> x=1,5
48.13 + 61 . 16
= 48 . ( 10 + 3 ) + ( 60 + 1 ) . 16
= [ 48 . 10 + 48.3 ] + [ 60 . 16 + 1 . 16 ]
= 624 + 976
= 1600
1, \(48.13+61.16=16.3.13+61.16=16.\left(39+61\right)=16.100=1600\)
\(2,5.6.32+60.15.2+3.16.5=5.6.2.16+60.15.2+3.5.4.4=60.16+60.30+60.4=60.\left(16+30+4\right)=60.50=3000\)
a; \(\dfrac{a}{b}\) + \(\dfrac{5}{6}\) = 1 - \(\dfrac{1}{8}\)
\(\dfrac{a}{b}\) + \(\dfrac{5}{6}\) = \(\dfrac{7}{8}\)
\(\dfrac{a}{b}\) = \(\dfrac{7}{8}-\dfrac{5}{6}\)
\(\dfrac{a}{b}=\) \(\dfrac{21}{24}\) - \(\dfrac{20}{24}\)
\(\dfrac{a}{b}=\dfrac{1}{24}\)
b; \(\dfrac{5}{8}-\dfrac{a}{b}\) = \(\dfrac{1}{4}+\dfrac{1}{6}\)
\(\dfrac{5}{8}-\dfrac{a}{b}\) = \(\dfrac{3}{12}+\dfrac{2}{12}\)
\(\dfrac{5}{8}-\) \(\dfrac{a}{b}\) = \(\dfrac{5}{12}\)
\(\dfrac{a}{b}\) = \(\dfrac{5}{8}-\dfrac{5}{12}\)
\(\dfrac{a}{b}\) = \(\dfrac{15}{24}\) - \(\dfrac{10}{24}\)
\(\dfrac{a}{b}\) = \(\dfrac{5}{24}\)
c; \(\dfrac{5}{6}\) - \(\dfrac{1}{4}\) - \(\dfrac{a}{b}\) = \(\dfrac{1}{2}\)
\(\dfrac{10}{12}-\dfrac{3}{12}\) - \(\dfrac{a}{b}\) = \(\dfrac{1}{2}\)
\(\dfrac{7}{12}\) - \(\dfrac{a}{b}\) = \(\dfrac{1}{2}\)
\(\dfrac{a}{b}\) = \(\dfrac{7}{12}\) - \(\dfrac{1}{2}\)
\(\dfrac{a}{b}\) = \(\dfrac{7}{12}-\dfrac{6}{12}\)
\(\dfrac{a}{b}=\dfrac{1}{12}\)
a. \(\left(a^5\right)^7=a^{5.7}=a^{35}\)
b. \(\left(a^6\right)^4:a^{12}=a^{6.4}:a^{12}=a^{24}:a^{12}=a^{24-12}=a^{12}\)
c.\(\left(2^3\right)^5:\left(2^3\right)^3=2^{3.5}:2^{3.3}=2^{15}:2^9=2^{15-9}=2^6=64\)
d. \(\left(3^2\right)^4:\left(3^3\right)^2=3^{2.4}:3^{3.2}=3^8:3^6=3^{8-6}=3^2=9\)