4/9 x 13/3 - 4/3 x 40/9
Ghi rõ cách giải
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
-x + 20 = - (-15) - (8) + 13
-x + 20 = 15 - 8 + 13
-x + 20 = 7 + 13
- x + 20 = 20
x = 20 - 20
x = 0
-(-10) + x = -13 + (-9) + (-6)
10 + x = -13 - 9 - 6
10 + x = -28
x = -28 - 10
x = -38
1. -x+20 = -(-15)-8+13
=> -x=15-8+13-20
=> -x=0
=> x=0
2. -(-10)+x=-13+(-9)+(-6)
=> 10+x=-13-9-6
=> x = -13-9-6-10
=> x = -38
3. 8-(-12)+10=-(-14)-x
=> 8+12+10=14-x
=> x = 14-8-12-10
=> x = -16
4. -(+12)+(-x)-(-3)=5-(-7)
=> -12-x+3=5+7
=> -x=5+7+12-3
=> -x=21
=> x=-21
5. 14-x+(-10)=-(-9)+(+15)
=> 14-x-10=9+15
=> -x=9+15-14+10
=> -x=20
=> x=-20
6. 12-(-17)+(-3)=-5+x
=> 12+17-3+5=x
=> x=31
7. x-(-19)-(+32)=14-(+16)
=> x+19-32=14-16
=> x=14-16+32-19
=> x=11
8. x-|-15|-|7|=-(-9)+|-5|
=> x-15-7=9+5
=> x=9+5+7+15
=> x=36
9. 15-x+17=13-(-21)
=> 15-x+17=13+21
=> -x=13+21-15-17
=> -x=2
=> x=-2
10. -|-5|-(-x)+4=3-(-25)
=> -5+x+4=3+25
=> x=3+25-4+5
=> x=29
= (3/7 + 4/7) + (8/13 + 18/13) + (7/9 + 11/9)
= 7/7 + 26/3 + 18/9
= 1 + 2+ 2
=5
=(3\7+4\7)+(8\13 +18|13)+(7\9+11\9)
=7\7+26\13+18\9
=1+2+2
=5
a) \(\left(56\times27+56\times35\right)\div62=56\times\left(27+35\right)\div62=56\times62\div62=56\)
b) \(\frac{0,18\times1230+0,9\times4567\times2+3\times5310\times6}{1+4+7+10+....+52+55-514}\)
\(=\frac{0,18\times1230+\left(0,9\times2\right)\times4567+\left(3\times6\right)\times5310}{1+4+5+.....+52+55-514}\)
\(=\frac{0,18\times1230+0,18\times4567+0,18\times5310}{1+4+7+...+52+55-514}\)
\(=\frac{0,18\times\left(1230+4567+5310\right)}{\left(55+1\right)\times55\div2-514}\)
\(=\frac{0,18\times11107}{971}=\frac{1999,26}{971}\)
mình ra cũng giống bạn Forever _ Alone nhé!!!Chẳng qua mình không biết viết phân số
\(\frac{4}{9}\).\(\frac{13}{3}\)-\(\frac{4}{3}\).\(\frac{40}{9}\)=\(\frac{4.13}{9.3}\)-\(\frac{4.40}{3.9}\)
=\(\frac{\left(4.13\right)-\left(4.40\right)}{9.3}\)
= \(\frac{4\left(13-40\right)}{27}\)
=\(\frac{4\left(-27\right)}{27}\)
=-4
\(\frac{4}{9}\cdot\frac{13}{3}-\frac{4}{3}\cdot\frac{40}{9}\)
\(=\frac{4}{3}\cdot\frac{13}{9}-\frac{4}{3}\cdot\frac{40}{9}\)
\(=\frac{4}{3}\cdot\left(\frac{13}{9}-\frac{40}{9}\right)\)
\(=\frac{4}{3}\cdot-3=-4\)