3x5/7+5/7x6+5/7
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a) (36 + 54) x 7 + 7 x 9 + 7=
= 90 x 7 + 7x 9 + 7 x1 =
= 7 x ( 90 + 9 +1) =
= 7 x 100 = 700
b) 5/7 x 3 + 5/7 x 6 + 5/7 =
= 5/7 x (3 + 6 + 1) =
= 5/7 x 10 = 50/7
2/5 + 3/4 - 4/7 = 23/20 - 4/7 = 81/140
7/9 : 2/3 x 5/4 = 7/6 x 5/4 = 35/24
4/5 x (7/10 - 1/2) = 4/5 x 1/5 = 4/25
a) \(\dfrac{2}{5}+\dfrac{3}{4}-\dfrac{4}{7}\)
\(=\dfrac{56}{140}+\dfrac{105}{140}-\dfrac{80}{140}\)
\(=\dfrac{56+105-80}{140}\)
\(=\dfrac{81}{140}\)
b) \(\dfrac{7}{9}:\dfrac{2}{3}\times\dfrac{5}{4}\)
\(=\dfrac{7}{9}\times\dfrac{3}{2}\times\dfrac{5}{4}\)
\(=\dfrac{7\times3\times5}{9\times2\times4}\)
\(=\dfrac{35}{24}\)
c) \(\dfrac{4}{5}\times\left(\dfrac{7}{10}-\dfrac{1}{2}\right)\)
\(=\dfrac{4}{5}\times\left(\dfrac{7}{10}-\dfrac{5}{10}\right)\)
\(=\dfrac{4}{5}\times\dfrac{1}{5}\)
\(=\dfrac{4}{25}\)
\(\left(x\cdot2,4-4,2\right)\div x=1\)
\(\Rightarrow x\cdot2,4-4,2=x\)
\(\Rightarrow x\cdot2,4=x+4,2\)
\(\Rightarrow\frac{12x}{5}=\frac{5x+21}{5}\)
\(\Rightarrow12x=5x+21\)
\(\Rightarrow12x-5x=21\)
\(\Rightarrow7x=21\Rightarrow x=\frac{21}{7}=3\)
Vậy x = 3
\(\frac{1}{1\cdot3}+\frac{1}{3\cdot5}+...+\frac{1}{x\left(x+2\right)}\)
\(=\frac{1}{2}\cdot\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{x}-\frac{1}{x+2}\right)\)
\(=\frac{1}{2}\cdot\left(1-\frac{1}{x+2}\right)\)
\(=\frac{1}{2}\cdot\frac{x+1}{x+2}\)
\(=\frac{x+1}{2x+2}\)
con Nguyễn Kim Ngân ngu vãi tao ko biết thì tao mới phải hỏi
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