(X-7)x(X-5)x(X-4)x(X-2)=72
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Câu 1:15/35=3/7
216/270=4/5
250/750=1/3
Câu 2:8/18,12/27,16/36,20/45,24/54
Câu 3:1/2=2/4=3/6=4/8=5/10
Câu 4:2×3×5/2×7×5=30/70=3/7
Tk mình nhé bn!
Bài 1:
\(\frac{15}{35}=\frac{3}{7}\)
\(\frac{216}{270}=\frac{4}{5}\)
\(\frac{250}{750}=\frac{1}{3}\)
Bài 2:
5 phân số bằng phân số \(\frac{4}{9}\) là: \(\frac{8}{18};\frac{12}{27};\frac{16}{36};\frac{20}{45};\frac{24}{54}\)
Bài 3:
\(\frac{1}{2};\frac{2}{4};\frac{3}{6};\frac{4}{8};\frac{5}{10}\)
Bài 4:
\(\frac{2x3x5}{2x7x5}=\frac{3}{7}\)
\(a,1\dfrac{4}{7}.3\dfrac{4}{11}.3\dfrac{11}{15}.5\dfrac{5}{8}\)
\(=\dfrac{11}{7}.\dfrac{27}{11}.\dfrac{56}{15}.\dfrac{45}{8}\)
\(=\dfrac{11.27.56.45}{7.11.15.8}\)
\(=\dfrac{1.3.7.3}{1.1.1.1}\)
\(=63\)
\(b,\dfrac{3}{4}.1\dfrac{1}{2}+\dfrac{3}{4}.\dfrac{1}{2}\)
\(=\dfrac{3}{4}.\left(1\dfrac{1}{2}+\dfrac{1}{2}\right)\)
\(=\dfrac{3}{4}.2\)
\(=\dfrac{3}{2}\)
\(a.\frac{19}{5}\cdot\frac{4}{7}+\frac{3}{7}\cdot\frac{19}{5}-\frac{4}{5}\)
\(=\frac{19}{5}\cdot\left(\frac{4}{7}+\frac{3}{7}\right)-\frac{4}{5}\)
\(=\frac{19}{5}\cdot1-\frac{4}{5}\)
\(=\frac{19}{5}-\frac{4}{5}=\frac{15}{5}=3\)
\(b.2\frac{2}{7}\cdot5\frac{2}{5}+\frac{16}{7}\cdot1\frac{3}{5}+\frac{1}{2}\)
\(=\frac{16}{7}\cdot\frac{27}{5}+\frac{16}{7}\cdot\frac{8}{5}+\frac{1}{2}\)
\(=\frac{16}{7}\cdot\left(\frac{27}{5}+\frac{8}{5}\right)+\frac{1}{2}\)
\(=\frac{16}{7}\cdot7+\frac{1}{2}\)
\(=16+\frac{1}{2}=\frac{33}{2}\)
\(c.\frac{3}{7}\cdot3\frac{3}{4}-\frac{3}{7}\cdot\frac{5}{4}-\frac{1}{4}\)
\(=\frac{3}{7}\cdot\frac{15}{4}-\frac{3}{7}\cdot\frac{5}{4}-\frac{1}{4}\)
\(=\frac{3}{7}\cdot\left(\frac{15}{4}-\frac{5}{4}\right)-\frac{1}{4}\)
\(=\frac{3}{7}\cdot\frac{5}{2}-\frac{1}{4}\)
\(=\frac{15}{14}-\frac{1}{4}=\frac{23}{28}\)
Chú ý: \(\cdot:\times\)
\(a,\dfrac{4}{15}:\dfrac{4}{7}< x< \dfrac{2}{5}\times\dfrac{10}{3}\\ \Leftrightarrow\dfrac{7}{15}< x< \dfrac{4}{3}\\ \Leftrightarrow x=1\)
\(b,\dfrac{3}{5}\times\dfrac{3}{7}+\dfrac{2}{5}\times\dfrac{4}{7}=\dfrac{9}{35}+\dfrac{8}{35}=\dfrac{17}{35}\)
(x-7)(x-5)(x-4)(x-2)= 72
<=>(x-7)(x-2)(x-5)(x-4)=72
<=>(x2 -9x +14)(x2 -9x +20)= 72
đặt x2 -9x +17 = a ta có :
(a-3)(a+3)=72
<=>a2 - 9 = 72
<=> a = 9
=> x2 - 9x + 17 = 9
<=> x2 - 8x - x +8 = 0
<=> (x-1)(x-8) = 0
<=> x - 1 = 0 <=> x = 1
x - 8 = 0 x = 8
K MIK NHA