Tìm x biết , 4x-8=255 : 220
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8x + 3x = 220
=> (8 + 3)x = 220
=> 11x = 220
=> x = 220 : 11
=> x = 20
Ta thấy \(\left|x+\frac{1}{8}\right|\ge0\forall x;\left|x+\frac{2}{8}\right|\ge0\forall x;\left|x+\frac{5}{8}\right|\ge0\forall x\)
\(\Rightarrow\left|x+\frac{1}{8}\right|+\left|x+\frac{2}{8}\right|+\left|x+\frac{5}{8}\right|\ge0\)
\(\Rightarrow4x\ge0\Rightarrow x\ge0\)
\(\Rightarrow x+\frac{1}{8}+x+\frac{2}{8}+x+\frac{5}{8}=4x\)
\(\Rightarrow3x+1=4x\)
=> x = 1 (t/m)
Vậy x=1
Vì \(5x=2y=3z\)
\(\Rightarrow5x:30=2y:30=3z:30\)
\(\Rightarrow\frac{x}{6}=\frac{y}{15}=\frac{z}{10}\)
Lại có: \(x+y-2=220\Rightarrow x+y=222\)
Áp dụng tc của dãy tỉ số bằng nhau ta có:
\(\frac{x}{6}=\frac{y}{15}=\frac{z}{10}=\frac{x+y}{6+15}=\frac{222}{21}=\frac{74}{7}\)
\(\Rightarrow\hept{\begin{cases}x=\frac{74}{7}.6=\frac{444}{7}\\y=\frac{74}{7}.15=\frac{1110}{7}\\z=\frac{74}{7}.10=\frac{740}{7}\end{cases}}\)
Vậy ...
Bài 1:
\(5x=2y=3z\)
\(\Rightarrow5x:30=2y:30=3z:30\)
\(\Rightarrow\frac{x}{6}=\frac{y}{15}=\frac{z}{10}\)
Vì \(x+y-2=220\Rightarrow x+y=222\)
Áp dụng tc của dãy tỉ số bằng nhau ta có:
\(\frac{x}{6}=\frac{y}{15}=\frac{z}{10}=\frac{x+y}{6+15}=\frac{222}{21}=\frac{74}{7}\)
\(\Rightarrow\hept{\begin{cases}x=\frac{74}{7}.6=\frac{444}{7}\\y=\frac{74}{7}.15=\frac{1110}{7}\\z=\frac{74}{7}.10=\frac{740}{7}\end{cases}}\)
a) \(4x^3-36x=0\)
\(\Leftrightarrow4x\left(x^2-9\right)=0\)
\(\Leftrightarrow4x\left(x+3\right)\left(x-3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}4x=0\\x+3=0\\x-3=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-3\\x=3\end{matrix}\right.\)
b) \(\left(x-2\right)^2-4x+8=0\)
\(\Leftrightarrow\left(x-2\right)^2-\left(4x-8\right)=0\)
\(\Leftrightarrow\left(x-2\right)^2-4\left(x-2\right)=0\)
\(\Leftrightarrow\left(x-2\right)\left(x-2-4\right)=0\)
\(\Leftrightarrow\left(x-2\right)\left(x-6\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x-6=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=6\end{matrix}\right.\)
c) \(x^3+\left(x+3\right)\left(x-9\right)=-27\)
\(\Leftrightarrow\left(x^3+27\right)+\left(x+3\right)\left(x-9\right)=0\)
\(\Leftrightarrow\left(x+3\right)\left(x^2-3x+9\right)+\left(x+3\right)\left(x-9\right)=0\)
\(\Leftrightarrow\left(x+3\right)\left(x^2-3x+9+x-9\right)=0\)
\(\Leftrightarrow\left(x+3\right)\left(x^2-2x\right)=0\)
\(\Leftrightarrow x\left(x+3\right)\left(x-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+3=0\\x-2=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-3\\x=2\end{matrix}\right.\)
Lời giải:
$4x-8=2^{55}-2^{20}=2^{35}$
$4x=8+2^{35}$
$x=\frac{8+2^{35}}{4}=2+2^{33}$