Question

[nguyễn khánh ngọc]

Tìm các số a;b . Biết

|5a-6b+300|mũ2007 =[2a-3b]mũ 2008=0

Answer 1

[Phạm Nguyễn Tất Đạt]

Ta có:\(\left|5a-6b+300\right|^{2007}=0\Leftrightarrow5a-6b+300=0\Leftrightarrow5a=-300+6b\)

\(\left|2a-3b\right|^{2008}=0\Leftrightarrow2a-3b=0\Leftrightarrow2a=3b\Leftrightarrow a=\frac{3}{2}b\)

\(\Rightarrow5\cdot\frac{3}{2}b=-300+6b\)

\(\Rightarrow7,5b=-300+6b\)

\(\Rightarrow1,5b=-300\)

\(\Rightarrow b=-200\)

\(\Rightarrow a=-300\)