720 ; {41-(2x - 5) } = 23.5
2x.4=128
x15=x
(2x + 1)3=125
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ĐKXĐ: \(x\notin\left\{10;-10\right\}\)
Ta có: \(\dfrac{720}{x+10}+4=\dfrac{720}{x-10}\)
\(\Leftrightarrow\dfrac{720\left(x-10\right)}{\left(x+10\right)\left(x-10\right)}+\dfrac{4\left(x^2-100\right)}{\left(x+10\right)\left(x-10\right)}=\dfrac{720\left(x+10\right)}{\left(x+10\right)\left(x-10\right)}\)
Suy ra: \(720x-7200+4x^2-400-720x-7200=0\)
\(\Leftrightarrow4x^2=14800\)
\(\Leftrightarrow x^2=3700\)
hay \(x\in\left\{10\sqrt{37};-10\sqrt{37}\right\}\)
ĐKXĐ: \(x\ne\pm10\)
\(\Leftrightarrow\dfrac{180}{x-10}-\dfrac{180}{x+10}=1\)
\(\Leftrightarrow\dfrac{180\left(x+10-x+10\right)}{\left(x-10\right)\left(x+10\right)}=1\)
\(\Leftrightarrow\dfrac{3600}{x^2-100}=1\)
\(\Rightarrow x^2-100=3600\)
\(\Leftrightarrow x^2=3700\)
\(\Leftrightarrow x=\pm10\sqrt{37}\) (thỏa mãn)
a) Ta có:
192 = 26.3
102 = 2.3.17
UCLN(192,102) = 2.3 = 6
b) Ta có:
216 = 23.33
720 = 24.32.5
UCLN(216,720) = 23.32 = 8.9 = 72
c) Ta có:
480 = 25.3.5
720 = 24.32.5
48 = 24.3
UCLN(480,720,48) = 25.3 = 32.3 = 96
a: UCLN(192;102)=6
b: UCLN(216;720)=72
c: UCLN(480;720;48)=48
720:[41-(2x-5)]=2^3.5
720:[41-2x+5]=40
[41+5-2x]=720:40
46-2x=18
2x=46-18
2x=28
x=14
a, 2x.4=128
2x=128:4
2x=32
2x=25
x=5
Vay x=5
b, x15=x
x=1
Vay x=1