Tìm số hữu tỉ x, biết
\(3x-\dfrac{5}{3}=x-\dfrac{1}{4}\)
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0,(1) = 1/9
0.(01) = 1/99
1,(8) = 17/9
0,27 = 3/11
\(\dfrac{37}{63}\) : 5 + \(\dfrac{37}{63}\) : 14 = \(\dfrac{37}{63}\) x ( 1/5 + 1/14) # \(\dfrac{37}{63}\) : (5 + 14)
\(\dfrac{25}{12}\).0,8 + \(\dfrac{25}{12}\) . 0,5 = \(\dfrac{25}{12}\). ( 0,8 + 0,5)
0,8 : { 0,2 - 8 .[ \(\dfrac{7}{48}\)+ ( \(\dfrac{5}{24}\) - \(\dfrac{5}{26}\) ) ] }
= 0,8 : { 0,2 - 8.[ \(\dfrac{7}{48}\) - \(\dfrac{5}{48}\)]}
= 0,8 : { 0,2 - 8. \(\dfrac{2}{48}\)}
= 0,8 : (0,2 - 1/3)
= 0,8 : (-2/15)
= - 0,8 . 15/2
= - 6
\([\)( \(\dfrac{3}{5}\) - \(\dfrac{1}{3}\)) .6 - \(\dfrac{1}{3}\)\(]\) .5
=\([\) \(\dfrac{4}{15}\) .6 - \(\dfrac{1}{3}\) \(]\) . 5
= \([\) \(\dfrac{4}{5}\) .2 - \(\dfrac{1}{3}\) \(]\) . 5
= 8 - \(\dfrac{5}{3}\)
= 19/3
= 12
( 1 - \(\dfrac{2}{3}\) - \(\dfrac{1}{4}\) ) .( \(\dfrac{4}{5}\) - \(\dfrac{3}{4}\) )2
= ( \(\dfrac{1}{3}-\dfrac{1}{4}\)).\(\dfrac{1}{20^2}\)
= \(\dfrac{1}{12}\) . \(\dfrac{1}{400}\)
= \(\dfrac{1}{4800}\)
A = x2 +10x + 1
A = (x2 + 2.5x + 25) - 24
A = (x+5)2 - 24
( x + 5)2 ≥ 0 ⇔ (x + 5)2 - 24 ≥ -24
A (min) = - 24 ⇔ x = -5
\(3x-\dfrac{5}{3}=x-\dfrac{1}{4}\\ =>3x-x=\dfrac{5}{3}-\dfrac{1}{4}\\ =>2x=\dfrac{17}{12}\\ =>x=\dfrac{17}{24}\)