- Cho tám giác ABC : Góc A =90 độ . Trên cạnh BC lấy E sao cho BE = BA tia phân giác của góc B cắt AC tại D
- So sánh DA VÀ DE
- Tianh góc BED
- DE cắt AB tại M So sánh góc AMD và ECD
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Giải:
\(\dfrac{9}{A}\) = \(\dfrac{B}{8}\) = \(\dfrac{15}{20}\) = \(\dfrac{C}{24}\)
\(\dfrac{9}{A}\) = \(\dfrac{15}{20}\) = \(\dfrac{3}{4}\)
A = 9 : \(\dfrac{3}{4}\) = 9 x \(\dfrac{4}{3}\) = 12
\(\dfrac{B}{8}\) = \(\dfrac{15}{20}\) = \(\dfrac{3}{4}\)
B = \(\dfrac{3}{4}\) x 8 = 6
\(\dfrac{C}{24}\) = \(\dfrac{15}{20}\) = \(\dfrac{3}{4}\)
C = \(\dfrac{3}{4}\) x 24 = 18
Vậy A + B - C = 12 + 6 - 18 = 0
Chọn b.0
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Baking also helps me to relax after a busy week with lots of homework
![](https://rs.olm.vn/images/avt/0.png?1311)
1 While I was riding home, I saw an accident
2 When he was young, he used to smoke a lot
3 While Jane was taking a bath, the phone rang three times
4 While I was having lunch, James arrived
5 While we were having dinner, the lights went out
6 When I heard the doorbell, I went to the door
7 While we were standing outside the cinema, someone picked my pocket
8 While I was having breakfast, the telephone rang
9 While they were cooking, somebody broke into their house
10 While I was learning my old lessons, my sister was watching TV
1 While I was riding home, I saw an accident
2 When he was young, he smoked a lot
3 While Jane was taking a bath, the phone rang three times
4 While I was having lunch, James arrived
5 While we were having dinner, the light went out
![](https://rs.olm.vn/images/avt/0.png?1311)
B. Reading
1 Students often play soccer, table tennis or badminton
2 They sometimes go swimming in the swimming pools
3 They often practice playing musical instruments in the school music room
4 They usually rehearse plays
5 They often get together and talk about their stamps
Xét ΔBAD và ΔBED có
BA=BE
\(\widehat{ABD}=\widehat{EBD}\)
BD chung
Do đó: ΔBAD=ΔBED
=>\(\widehat{BAD}=\widehat{BED}\)
=>\(\widehat{BED}=90^0\)
Ta có: ΔBAD=ΔBED
=>DA=DE
Xét ΔDAM vuông tại A và ΔDEC vuông tại E có
DA=DE
\(\widehat{ADM}=\widehat{EDC}\)(hai góc đối đỉnh)
Do đó: ΔDAM=ΔDEC
=>\(\widehat{DMA}=\widehat{DCE}\)