-4x-(-7)=-11.35

=> -4x+7=-385

=> -4x=-385-7

=> -4x=-392

=> x=(-392)÷(-4)

=> x=98

thank you 

(17x - 25) : 2³ + 65 = 9²

(17x - 25) : 8 + 65 = 81

(17x - 25) : 8 = 81 - 65

(17x - 25) : 8 = 16

17x - 25 = 16 x 8

17x - 25 = 128

17x = 128 + 25

17x = 153

x = 153 : 17

x = 9.

\(\left(17x-25\right):2^3+65=9^2\)

\(=>\left(17x-25\right):8+65=81\)

\(=>\left(17x-25\right):8=81-65\)

\(=>\left(17x-25\right):8=16\)

\(=>17x-25=16.8\)

\(=>17x-25=128\)

\(=>17x=128+25\)

\(=>17x=153\)

\(=>x=153:17\)

\(=>x=9\)

\(#Nulc`\)

    -5 + (-37 - 45 + 51) - (-37 + 51)

=  -5  - 37 - 45 + 51 + 37 - 51

=  - (5 + 45) - (37 - 37) + (51 - 51)

= - 50 - 0 + 0

= - 50

  - (15 - 47 + 58) + (15 - 47 ) + 3

= - 15 + 47 - 58 + 15 - 47 + 3

= (-15 + 15) + (47 - 47) - (58 - 3)

= 0 + 0 - 55

= - 55

  (53 - 45 - 49) - (53 + 45 - 49)

= 53 -  45 - 49 - 53 - 45 + 49

= (53 - 53) + (-49 + 49) - (45 + 45)

= 0 + 0 - 90

= - 90 

    13 - 15 + 49 - 13 + 15 - 48

=  (13 - 13) + (-15 + 15) + (49 - 48)

= 0 + 0 + 1

=  1 

-6.6.6.3.2.2.(-3)

= -36.6.3.2.2.(-3)

= -216.3.2.2.(-3)

= -648.2.2.(-3)

= -1296.2.(-3)

= -2592.(-3)

= 7776

-6.6.6.3.2.2.(-3)

= -6.6.6.6.(-6)

= 6⁵

= 7776

\(17.\left(-238\right)+17.138\)

\(=17.\left(-238+138\right)\)

\(=17.-100=-1700\)

17.(-238) + 17.138

= -17.(238 - 128)

= -17.100

= -1700

2.3² - 4³ : (-16.2)

= 2.9 - 64 : (-32)

= 18 - (-2)

= 18 + 2

= 20

\(2.3^2-4^3:\left(-16.2\right)\)

\(=2.9-64:\left(-32\right)\)

\(=18-\left(-2\right)=18+2=20\)

\(-200:\left\{5\left[360-\left(290+2.5^2\right)\right]\right\}\)

\(=-200:\left\{5\left[360-\left(290+2.25\right)\right]\right\}\)

\(=-200:\left\{5\left[360-\left(290+50\right)\right]\right\}\)

\(=-200:\left\{5\left[360-340\right]\right\}\)

\(=-200:\left\{5.20\right\}\)

\(=-200:100=-2\)

-200 : {5.[360 - (290 + 2.5²)]}

= -200 : {5.[360 - (290 + 2.25)]}

= -200 : {5.[360 - (290 + 50)]}

= -200 : {5.[360 - 340]}

= -200 : {5.20}

= -200 : 100

= (-2)

15 - (+72) + (+75) + (+72)

= 15 - 72 + 75 + 72

= -57 + 75 + 52

= 18 + 52

= 70

\(\Leftrightarrow6-2xy=3x\Leftrightarrow6=x\left(2y+3\right)\)

\(\Rightarrow x=\dfrac{6}{2y+3}\left(y\ne-\dfrac{3}{2}\right)\) (1)

x nguyên khi \(6⋮\left(2y+3\right)\Rightarrow\left(2y+3\right)=\left\{-6;-3;-2;-1;1;2;3;6\right\}\)

\(\Rightarrow y=\left\{-\dfrac{9}{2};-3;-\dfrac{5}{2};-2;-1;-\dfrac{1}{2};0;\dfrac{3}{2}\right\}\) Do y nguyên

\(\Rightarrow y=\left\{-3;-2;-1;0\right\}\) Thay lần lượt các giá trị của y vào (1) để tìm các giá trị tương ứng của x

A = 12.(-47) + 12.(-19) + (-66).88

A = -12.(47 + 19)  - 66.88

A = -12.66 - 66.88

A = -66.(12 + 88)

A = -66. 100

A = - 6600