Given a square with the length of one side is 8 cm and a isosceles triangle with the length of its base is 12 cm. If the area of the square is equal to the area of the isosceles triangle then what is the length of the height of the isosceles triangle, in cm?
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24 tháng 8 2019
There are 18 students have neither a dog or a cat
_ Study well _
LT
1
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10 tháng 6 2018
We have : \(A=\)\(9x^2+8-12\)
=\(\left[\left(3x\right)^2-2.3x.2+4\right]+4\)
\(=\left(3x-2\right)^2+4\ge4\)(first)
But \(B=2\)(2)
From (1) and (2)
\(\Rightarrow A>B\)
HT
0
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L
0
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L
0
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L
0
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L
0
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32/3 nha ban