Ta có \(\widehat{xOy}\) và \(\widehat{yOz}\) là hai góc kề nhau nên:

\(\widehat{xOy}+\widehat{yOz}=\widehat{xOz}\)

\(\Rightarrow\widehat{xOz}=130^o+60^o=190^o\)

\(\widehat{xoz}=130+60=190^o\)

\(\text{∘ Ans}\)

\(\downarrow\)

\(A=\dfrac{8}{9}-\dfrac{1}{72}-\dfrac{1}{56}-\dfrac{1}{42}-...-\dfrac{1}{6}-\dfrac{1}{2}\)

`=`\(\dfrac{8}{9}-\left(\dfrac{1}{2}+\dfrac{1}{6}+...+\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}\right)\)

`=`\(\dfrac{8}{9}-\left(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{6\cdot7}+\dfrac{1}{7\cdot8}+\dfrac{1}{8\cdot9}\right)\)

`=`\(\dfrac{8}{9}-\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{8}-\dfrac{1}{9}\right)\)

`=`\(\dfrac{8}{9}-\left[1-\left(\dfrac{1}{2}-\dfrac{1}{2}\right)-\left(\dfrac{1}{3}-\dfrac{1}{3}\right)-...-\left(\dfrac{1}{8}-\dfrac{1}{8}\right)-\dfrac{1}{9}\right]\)

`=`\(\dfrac{8}{9}-\left(1-\dfrac{1}{9}\right)\)

`=`\(\dfrac{8}{9}-\dfrac{8}{9}=0\)

Vậy, ` A = 0.`

\(A=\dfrac{8}{9}-\left(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+...+\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}\right)=\)

\(A=\dfrac{8}{9}-\left(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{7.8}+\dfrac{1}{8.9}\right)=\)

\(A=\dfrac{8}{9}-\left(\dfrac{2-1}{1.2}+\dfrac{3-2}{2.3}+\dfrac{4-3}{3.4}+...+\dfrac{9-8}{8.9}\right)\)

\(A=\dfrac{8}{9}-\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+..+\dfrac{1}{8}-\dfrac{1}{9}\right)\)

\(A=\dfrac{8}{9}-\left(1-\dfrac{1}{9}\right)=0\)

a) -1/24 - [ 1/4 - ( 1/2 - 7/8 )]

= -1/24 - [ 1/4 +3/8 ]

= -1/24 - 5/8

= -2/3.

a) -1/24 - [ 1/4 - ( 1/2 - 7/8 )]

= -1/24 - [ 1/4 +3/8 ]

= -1/24 - 5/8

= -2/3.

\(...=1-\dfrac{1}{2}-\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{3}+\dfrac{1}{4}-...-\dfrac{1}{98}+\dfrac{1}{99}\)

\(=\dfrac{1}{99}\) (Bạn xem lại đề)

đề này nó cứ lạ lạ kiểu gì ấy

\(...-\dfrac{1}{24}-\left[\dfrac{1}{4}--\dfrac{3}{8}\right]=-\dfrac{1}{24}-\dfrac{5}{8}=-\dfrac{2}{3}\)

\(-\dfrac{1}{24}-\left[\dfrac{1}{4}-\left(\dfrac{1}{2}-\dfrac{7}{8}\right)\right]\)

\(=-\dfrac{1}{24}-\left[\dfrac{1}{4}-\left(\dfrac{4}{8}-\dfrac{7}{8}\right)\right]\)

\(=-\dfrac{1}{24}-\left(\dfrac{1}{4}+\dfrac{3}{8}\right)\)

\(=-\dfrac{1}{24}-\left(\dfrac{2}{8}+\dfrac{3}{8}\right)\)

\(=-\dfrac{1}{24}-\dfrac{5}{8}\)

\(=-\dfrac{1}{24}-\dfrac{15}{24}\)

\(=\dfrac{-16}{24}\)

\(=-\dfrac{2}{3}\)

Bạn xem lại đề

dung de bn ah

...\(a=\left[\left(\left(50-1\right):1+1\right):2\right]\left(50+1\right)=25.51=1275\)

\(...a1=\left[\left(\left(98-35\right):3+1\right):2\right]\left(35+98\right)=11.133=1463\)

\(\dfrac{2}{15}:\left(-\dfrac{29}{5}\right).\dfrac{29}{12}=\dfrac{2}{15}.\left(-\dfrac{5}{29}\right).\dfrac{29}{12}=-\dfrac{1}{18}\)

2/15 : (-5 4/5 ) . 2 5/12

= 2/15 : (-29/5 ) .29/12

= -2/87 . 29/12

= -1/18

a)\(...-\dfrac{22}{7}.\dfrac{6}{55}.\left(-\dfrac{7}{12}\right)=\dfrac{22}{7}.\dfrac{6}{55}.\dfrac{7}{12}=\dfrac{1}{5}\)

b) \(\dfrac{18}{39}.\left(-\dfrac{13}{8}\right):\left(-\dfrac{27}{4}\right)=-\dfrac{3}{4}.\left(-\dfrac{4}{27}\right)=\dfrac{1}{9}\)

`a)-3 1/7. 6/55.(-7/12)`

`= -22/7 . 6/55 . (-7/12) `

`= -12/35 . (-7/12 ) `

`= 1/5 `

`b)18/39.( -1 5/8) : (-6 3/4)`

`= 18/39 . (-13)/8 : (-27)/4 `

`= 18/39 . (-13)/8 . (-4)/27 `

`= (-3)/4 . (-4)/27`

`= 1/9`

`@` `\text {Ans}`

`\downarrow`

`a)`

\(1\dfrac{3}{5}\div\left(-5\dfrac{5}{7}\right)\)

`=`\(\dfrac{8}{3}\div\left(-\dfrac{30}{7}\right)\)

`=`\(\dfrac{8}{3}\cdot\left(-\dfrac{7}{30}\right)=-\dfrac{28}{45}\)

`b)`

\(-1\dfrac{1}{8}\cdot\dfrac{4}{51}\cdot\left(-11\dfrac{1}{3}\right)=-\dfrac{9}{8}\cdot\dfrac{4}{51}\cdot\left(-\dfrac{34}{3}\right)=-\dfrac{3}{34}\cdot\left(-\dfrac{34}{3}\right)=1\)

a)...\(\dfrac{8}{5}:\left(-\dfrac{40}{7}\right)=\dfrac{8}{5}.\left(-\dfrac{7}{40}\right)=-\dfrac{7}{25}\)

b) \(...-\dfrac{9}{8}.\dfrac{4}{51}\left(-\dfrac{34}{3}\right)=1\)