......................?

mik ko biết

mong bn thông cảm 

nha ................

6   \(n^5+5n=n^5-n+6n=n\left(n^4-1\right)+6n=n\left(n^2-1\right)\left(n^2+1\right)+6n\)

\(=n\left(n-1\right)\left(n+1\right)\left(n^2+1\right)+6n\)

vì n,n-1 là 2 số nguyên lien tiếp  \(\Rightarrow n\left(n-1\right)⋮2\Rightarrow n\left(n-1\right)\left(n+1\right)\left(n^2+1\right)⋮2\)

  n,n-1,n+1 là 3 sô nguyên liên tiếp \(\Rightarrow n\left(n-1\right)\left(n+1\right)⋮3\Rightarrow n\left(n-1\right)\left(n+1\right)\left(n^2+1\right)⋮3\)

\(\Rightarrow n\left(n-1\right)\left(n+1\right)\left(n^2+1\right)⋮2\cdot3=6\)

\(6⋮6\Rightarrow6n⋮6\Rightarrow n\left(n-1\right)\left(n+1\right)\left(n^2+1\right)-6n⋮6\Rightarrow n^5+5n⋮6\)(đpcm)

7   \(n\left(2n+7\right)\left(7n+1\right)=n\left(2n+7\right)\left(7n+7-6\right)=7n\left(n+1\right)\left(2n+7\right)-6n\left(2n+7\right)\)

\(=7n\left(n+1\right)\left(2n+4+3\right)-6n\left(2n+7\right)\)

\(=7n\left(n+1\right)\left(2n+4\right)+21n\left(n+1\right)-6n\left(2n+7\right)\)

\(=14n\left(n+1\right)\left(n+2\right)+21n\left(n+1\right)-6n\left(2n+7\right)\)

n,n+1,n+2 là 3 sô nguyên liên tiếp dựa vào bài 6 \(\Rightarrow n\left(n+1\right)\left(n+2\right)⋮6\Rightarrow14n\left(n+1\right)\left(n+2\right)⋮6\)

\(21⋮3;n\left(n+1\right)⋮2\Rightarrow21n\left(n+1\right)⋮3\cdot2=6\)

\(6⋮6\Rightarrow6n\left(2n+7\right)⋮6\)

\(\Rightarrow14n\left(n+1\right)\left(n+2\right)+21n\left(n+1\right)-6n\left(2n+7\right)⋮6\)

\(\Rightarrow n\left(2n+7\right)\left(7n+1\right)⋮6\)(đpcm)

......................?

mik ko biết

mong bn thông cảm 

nha ................

\(\frac{9}{5}\)S = 9+99+...+99...9 (50 chữ số 9)

             =10-1+10²-1+...+10⁵⁰-1

             =(10+10²+...+10⁵⁰)-(1+1+...+1) 

             =(10⁵¹-10) - 50

             =10⁵¹-60

\(\Rightarrow\)S=(10⁵¹-60)/\(\frac{9}{5}\)= 5(10⁵¹-60)/9

......................?

mik ko biết

mong bn thông cảm 

nha ................

\(\left(5x+2\right)\left(x-1\right)-3\left(x+3\right)^2-2\left(x-6\right)\left(x+6\right)\)

\(=5x^2-5x+2x-2-3\left(x^2+6x+9\right)-2\left(x^2-6^2\right)\)

\(=5x^2-3x-2-3x^2-18x-27-2x^2+72\)

\(=-21x+43\)

kết quả mik ra là -3x + 7 theo các bạn đúng ko

......................?

mik ko biết

mong bn thông cảm 

nha ................

\(đk:0\le x\le1\)

Ta có: \(\sqrt{x+x^2}=\sqrt{x\left(x+1\right)}\le\frac{x+x+1}{2},\sqrt{x-x^2}=\sqrt{x\left(1-x\right)}\le\frac{x+1-x}{2}\)

\(\Rightarrow VT\le x+1\)

Dấu "=" xra khi \(\hept{\begin{cases}x=x+1\\x=1-x\end{cases}\Leftrightarrow ko\exists x}\)

Vậy pt vô nghiệm

......................?

mik ko biết

mong bn thông cảm 

nha ................

a/ \(\left(2x+3\right)^2-\left(2x+1\right)\left(2x-1\right)=22\)

<=> \(\left(2x+3\right)^2-\left(4x^2-1\right)=22\)

<=> \(\left(2x+3\right)^2-4x^2+1=22\)

<=> \(\left(2x+3-2x\right)\left(2x+3+2x\right)=21\)

<=> \(3\left(4x+3\right)=21\)

<=> \(4x+3=7\)

<=> \(4x=4\)

<=> \(x=1\)

......................?

mik ko biết

mong bn thông cảm 

nha ................

\(P=3^2+6^2+9^2+....+30^2\)

    \(=\left(3.1\right)^2+\left(3.2\right)^2+\left(3.3\right)^2+....+\left(3.10\right)^2\)

      \(=3^2.1^{^2}+3^2.2^2+3^2.3^2+....+3^2.10^2\)

       \(=3^2.\left(1^2+2^2+3^2+...+10^2\right)\)

        \(=9.385\)

          \(=3465\)

Vậy P = 3465

1^2 + 2^2 + 3^2 + ... + 10^2 = 385

Co :

 P = 3^2 + 6^2 + 9^2 + ... + 30^2

 P = 3^2( 1^2 + 2^2 + 3^2 + ... + 10^2 )

 P = 9 . 385 

 P = 3465