a=3 và b=-11

??????????

\(f\left(1\right)=1^2+3m\cdot1+1^2=1+3m+1=2+3m\)

\(g\left(1\right)=1^2+\left(2m-1\right)\cdot1+m^2=1+\left(2m-1\right)+m^2=1+2m-1+m^2=2m+m^2\)

Để \(f\left(1\right)=g\left(1\right)\Rightarrow2+3m=2m+m^2\)

\(\Rightarrow2+m=m^2\)

\(\Rightarrow2=m^2-m\)

\(\Rightarrow2=m\left(m-1\right)\)

Ta có 2=-1 x (-2)= 1 x 2

P/S: Tự lập bảng giá trị

=\(\left(6.\frac{1}{4}+1+1\right):\left(\frac{-1}{2}-1\right)\)

=\(\frac{5}{2}\):\(\frac{\left(-3\right)}{2}\)=\(\frac{-10}{6}=\frac{-5}{3}\)

hok tốt

\(\left[6.\left(-\frac{1}{2}\right)^2-2.\left(-\frac{1}{2}\right)+1\right].\left(-\frac{1}{2}-1\right)\)

\(=\left(6.\frac{1}{4}-\left(-1\right)+1\right).\left(-\frac{3}{2}\right)\)

\(=\frac{3}{2}.\left(-\frac{3}{2}\right)\)

\(=-\frac{9}{4}\)

~Moon~

\(\frac{2^5.7+2^5}{2^5.5^2-2^5.3}=\frac{2^5.\left(7+1\right)}{2^5.\left(5^2-3\right)}=\frac{8}{22}\)

\(\frac{2^5.7+2^5}{2^5.5^2-2^5.3}\)

\(\frac{2^5.\left(7+1\right)}{2^5.\left(5^2-3\right)}\)=\(\frac{8}{22}=\frac{4}{11}\)

Hok tốt

\(A+B=x^2-2xy+3x^2+3xy+y+1=4x^2+xy+y+1\)

\(A-B=\left(x^2-2xy\right)-\left(3x^2+3xy+y+1\right)\)

              \(=x^2-2xy-3x^2-3xy-y-1=-2x^2-5xy-y-1\)

Suy ra x-1=0;

y-2=0

x-z=0

suy ra x=1;y=2;z=1

\(A=\frac{2^{12}\cdot27^3+20\cdot6^9}{2\cdot6^{10}+12^6\cdot3^5}\)

\(=\frac{2^{12}\cdot\left(3^3\right)^3+2^2\cdot5\cdot2^9\cdot3^9}{2\cdot2^{10}\cdot3^{10}+\left(2^2\right)^6\cdot3^6\cdot3^5}\)

\(=\frac{2^{12}\cdot3^9+2^{11}\cdot5\cdot3^9}{2^{11}\cdot3^{10}+2^{12}\cdot3^{11}}\)

\(=\frac{2^{11}\cdot3^9\left(2\cdot5\right)}{2^{11}\cdot3^{10}\left(2\cdot3\right)}\)

\(=\frac{2^{11}\cdot3^9\cdot10}{2^{11}\cdot3^{10}\cdot6}\)

\(=3\cdot\frac{10}{6}=\frac{30}{6}=5\)

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