x phần -5 = 6 phần -10
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VN
Võ Ngọc Phương
VIP
13 tháng 2 2024
a) \(x:\dfrac{7}{11}-\dfrac{2}{3}=\dfrac{4}{5}\)
\(=>x:\dfrac{7}{11}=\dfrac{4}{5}+\dfrac{2}{3}=\dfrac{12}{15}+\dfrac{10}{15}\)
\(=>x:\dfrac{7}{11}=\dfrac{22}{15}\)
\(=>x=\dfrac{22}{15}.\dfrac{7}{11}\)
\(=>x=\dfrac{14}{15}\)
b) \(\dfrac{12}{11}:x+\dfrac{5}{6}=\dfrac{1}{2}\)
\(=>\dfrac{12}{11}:x=\dfrac{1}{2}-\dfrac{5}{6}=\dfrac{3}{6}-\dfrac{5}{6}\)
\(=>\dfrac{12}{11}:x=\dfrac{-2}{6}\)
\(=>x=\dfrac{12}{11}:\dfrac{-2}{6}=\dfrac{12}{11}.\dfrac{-6}{2}\)
\(=>x=\dfrac{-36}{11}\)
DD
3
PT
13 tháng 2 2024
P={(a-3)-[a+3+a+2]}
P={a-3-2a-5}
P=-a-8
Q=[2a+3]-4
Q=2a-1
=>2a-1>-a-8
Hơi tắt nha bn
TX
1
VN
Võ Ngọc Phương
VIP
13 tháng 2 2024
a) \(2^3-5^3:5^2+12.2^2\)
\(=8-5+12.4\)
\(=8-5+48\)
\(=3+48\)
\(=51\)
b) \(5\left[\left(85-35:7\right):8+90\right]-50\)
\(=5\left[\left(85-5\right):8+90\right]-50\)
\(=5\left[80:8+90\right]-50\)
\(=5\left[10+90\right]-50\)
\(=5.100-50\)
\(=500-50\)
\(=450\)
c) \(2.\left[\left(7-3^3:3^2\right):2^2+99\right]-100\)
\(=2.\left[\left(7-3\right):4+99\right]-100\)
\(=2.\left[4:4+99\right]-100\)
\(=2.\left[1+99\right]-100\)
\(=2.100-100\)
\(=200-100\)
\(=100\)
d) \(2^7:2^2+5^4:5^3.2^4-3.2^5\)
\(=2^5+5.2^4-3.2^5\)
\(=32+5.16-3.32\)
\(=32+80-96\)
\(=112-96\)
\(=16\)
e) \(\left(3^5.3^7\right):3^{10}+5.2^4-7^3:7\)
\(=3^{12}:3^{10}+5.16-7^2\)
\(=3^2+80-49\)
\(=9+80-49\)
\(=89-49\)
\(=40\)
f) \(3^2.\left[\left(5^2-3\right):11\right]-2^4+2.10^3\)
\(=9.\left[\left(25-3\right):11\right]-16+2.1000\)
\(=9.\left[22:11\right]-16+2.1000\)
\(=9.2-16+2.1000\)
\(=18-16+2000\)
\(=2+2000\)
\(=2002\)
\(#WendyDang\)
\(\dfrac{x}{-5}=\dfrac{6}{-10}\)
\(x\cdot\left(-10\right)=6\cdot\left(-5\right)\)
\(x\cdot\left(-10\right)=\left(-30\right)\)
\(x=\left(-30\right):\left(-10\right)\)
\(x=3\)
Vậy \(x=3\)
\(\Rightarrow\dfrac{3}{-5}=\dfrac{6}{-10}\)