Quy đồng mẫu sô a 3 phần 25 và 40 phần 125 b 1 phần 3, 2 phần 15 và 4 phần 5.
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\(a,\),\(\frac{6}{7}\)và \(\frac{4}{9}\)
Ta có: \(\frac{6}{7}=\frac{6\times9}{7\times9}=\frac{54}{63}\) \(;\) \(\frac{4}{9}=\frac{4\times7}{9\times7}=\frac{28}{63}\)
\(b,\)\(\frac{5}{8}\)và \(\frac{3}{11}\)
Ta có: \(\frac{5}{8}=\frac{5\times11}{8\times11}=\frac{55}{88}\) \(;\) \(\frac{3}{11}=\frac{3\times8}{11\times8}=\frac{24}{88}\)
\(c,\)\(\frac{6}{7}\)và \(\frac{5}{21}\)
Ta có: \(\frac{6}{7}=\frac{6\times3}{7\times3}=\frac{18}{21}\) \(;\)\(\frac{5}{21}\)
\(d,\)\(\frac{7}{21}\)và \(\frac{23}{84}\)
Ta có: \(\frac{7}{21}=\frac{7\times4}{21\times4}=\frac{28}{84}\)\(;\)\(\frac{23}{84}\)
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a)\(\frac{35}{12}+\frac{12}{11}=\frac{385}{132}+\frac{144}{132}=\frac{529}{132}\)
\(\frac{8}{9} +\frac{2}{3}=\frac{8}{9}+\frac{6}{9}=\frac{14}{9}\)
\(\frac{7}{8}+\frac{1}{6}=\frac{21}{24}+\frac{4}{24}=\frac{25}{24}\)
b)\(3+\frac{5}{6}=\frac{18}{6}+\frac{5}{6}=\frac{23}{6}\)
\(\frac{11}{3}+2=\frac{11}{3}+\frac{6}{3}=\frac{17}{3}\)
\(\frac{1}{2}+\frac{5}{6}=\frac{3}{6}+\frac{5}{6}=\frac{8}{6}=\frac{4}{3}\)
\(\frac{6}{4}+\frac{3}{5}=\frac{30}{20}+\frac{12}{20}=\frac{42}{20}=\frac{21}{10}\)
\(\frac{23}{7}+\frac{2}{6}=\frac{23}{7}+\frac{1}{3}=\frac{69}{21}+\frac{7}{21}=\frac{76}{21}\)
#H
(Có gì sai thì sửa :)))
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Ta có: \(\frac{2}{3}=1-\frac{1}{3}\); \(\frac{3}{4}=1-\frac{1}{4}\)
Vì \(3< 4\)\(\Rightarrow\frac{1}{3}>\frac{1}{4}\)\(\Rightarrow1-\frac{1}{3}< 1-\frac{1}{4}\)
\(\Rightarrow\frac{2}{3}< \frac{3}{4}\)