mảnh vườn hcn có chiều dài = 12. cr = 3/4 chiều dài
a, tính chu vi hcn
b, tính diện tích hcn
c, người ta để ra 2/3 diện tích vườn để trồng rau . tính diện tích trồng rau
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\(\dfrac{3}{8}-\dfrac{1}{2}:\left(\dfrac{2x}{5}-\dfrac{2}{3}\right)=\dfrac{-8}{5}\\ \dfrac{3}{8}-\dfrac{1}{2}:\left(\dfrac{6x}{15}-\dfrac{10}{15}\right)=-\dfrac{8}{5}\\ \dfrac{3}{8}-\dfrac{1}{2}:\dfrac{6x-10}{15}=-\dfrac{8}{5}\\ \dfrac{1}{2}:\dfrac{6x-10}{15}=\dfrac{3}{8}+\dfrac{8}{5}\\ \dfrac{1}{2}\cdot\dfrac{15}{6x-10}=\dfrac{79}{40}\\ \dfrac{15}{6x-10}=\dfrac{79}{20}\\ 6x-10=15:\dfrac{79}{20}\\ 6x-10=\dfrac{300}{79}\\ 6x=\dfrac{300}{79}+10\\ 6x=\dfrac{1090}{79}\\ x=\dfrac{1090}{79}:6\\x =\dfrac{545}{237}\)
\(\dfrac{3}{8}-\dfrac{1}{2}:\left(\dfrac{2x}{5}-\dfrac{2}{3}\right)=-\dfrac{8}{5}\\ \dfrac{1}{2}:\left(\dfrac{2x}{5}-\dfrac{2}{3}\right)=\dfrac{79}{40}\\ \dfrac{2x}{5}-\dfrac{2}{3}=\dfrac{20}{79}\\ \dfrac{2x}{5}=\dfrac{218}{237}\\ 2x=\dfrac{1090}{237}\\ x=\dfrac{545}{237}\)
\(\dfrac{-13}{15}=\dfrac{-13}{5}\cdot\dfrac{1}{3}=\dfrac{-13}{5}:3\)
\(\dfrac{-2}{11}=-2\cdot\dfrac{1}{11}=-2:11\)
\(a.\dfrac{3}{4}:x=-\dfrac{1}{2}\\ x=\dfrac{3}{4}:\left(-\dfrac{1}{2}\right)\\ x=-\dfrac{3}{2}\\ b.x:\left(-\dfrac{2}{3}\right)=-\dfrac{5}{6}\\ x=\left(-\dfrac{5}{6}\right)\cdot\left(-\dfrac{2}{3}\right)\\ x=\dfrac{5}{9}\\ c.\dfrac{1}{2}:x-\dfrac{1}{2}=-\dfrac{3}{4}\\ \dfrac{1}{2}:x=-\dfrac{1}{4}\\ x=\dfrac{1}{2}:\left(-\dfrac{1}{4}\right)\\ x=-2\\ d.\dfrac{1}{2}\cdot x+\dfrac{3}{4}=-\dfrac{5}{6}\\ \dfrac{1}{2}\cdot x=-\dfrac{19}{12}\\ x=\dfrac{-19}{12}:\dfrac{1}{2}=-\dfrac{19}{12}\cdot2\\ x=-\dfrac{19}{6}\)
\(e.x:\dfrac{1}{2}+\dfrac{1}{2}=-\dfrac{5}{6}\\ x:\dfrac{1}{2}=-\dfrac{4}{3}\\ x=-\dfrac{4}{3}\cdot\dfrac{1}{2}\\ x=-\dfrac{2}{3}\\ g.\dfrac{4}{3}-\dfrac{1}{2}\cdot x=\dfrac{1}{2}\\ \dfrac{1}{2}\cdot x=\dfrac{5}{6}\\ x=\dfrac{5}{6}:\dfrac{1}{2}=\dfrac{5}{6}\cdot2\\ x=\dfrac{5}{3}\\ h.\dfrac{3}{8}\cdot x-\dfrac{1}{2}=\dfrac{3}{4}\\ \dfrac{3}{8}\cdot x=\dfrac{1}{4}\\ x=\dfrac{1}{4}:\dfrac{3}{8}=\dfrac{1}{4}\cdot\dfrac{8}{3}\\ x=\dfrac{2}{3}\)
\(a.\dfrac{3}{2}-4\cdot\left(\dfrac{1}{2}+\dfrac{3}{4}\right)\\ =\dfrac{3}{2}-4\cdot\dfrac{5}{4}\\ =\dfrac{3}{2}-5=-\dfrac{7}{2}\\ b.\left(-\dfrac{1}{3}+\dfrac{5}{6}\right)\cdot11-7\\ =\dfrac{1}{2}\cdot11-7\\ =\dfrac{11}{2}-7=-\dfrac{3}{2}\\ c.\left(\dfrac{5}{8}+\dfrac{-2}{7}\right):\dfrac{3}{4}+\left(\dfrac{3}{8}-\dfrac{5}{7}\right):\dfrac{3}{4}\\ =\left(\dfrac{5}{8}+\dfrac{-2}{7}\right)\cdot\dfrac{4}{3}+\left(\dfrac{3}{8}-\dfrac{5}{7}\right)\cdot\dfrac{4}{3}\\ =\dfrac{4}{3}\cdot\left(\dfrac{5}{8}-\dfrac{2}{7}+\dfrac{3}{8}-\dfrac{5}{7}\right)\)
\(\dfrac{4}{3}\cdot\left[\left(\dfrac{5}{8}+\dfrac{3}{8}\right)-\left(\dfrac{2}{7}+\dfrac{5}{7}\right)\right]\\ =\dfrac{4}{3}\cdot\left(1-1\right)=\dfrac{4}{3}\cdot0=0\)
\(d.\dfrac{\dfrac{3}{4}-\dfrac{3}{5}+\dfrac{3}{7}+\dfrac{3}{11}}{\dfrac{13}{4}-\dfrac{13}{5}+\dfrac{13}{7}+\dfrac{13}{11}}\\ =\dfrac{3\cdot\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{11}\right)}{13\cdot\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{11}\right)}=\dfrac{3}{13}\)
a)
\(\dfrac{3}{2}-4\left(\dfrac{1}{2}+\dfrac{3}{4}\right)\\ =\dfrac{3}{4}-4\left(\dfrac{2}{4}+\dfrac{3}{4}\right)\\ =\dfrac{3}{4}-4\cdot\dfrac{5}{4}\\ =\dfrac{3}{4}-5\\ =-\dfrac{17}{4}\)
b)
\(\left(-\dfrac{1}{3}+\dfrac{5}{6}\right)\times11-7\\ =\left(-\dfrac{2}{6}+\dfrac{5}{6}\right)\times11-7\\ =\dfrac{1}{2}\times11-7\\ =\dfrac{11}{2}-7\\ =-\dfrac{3}{2}\)
c)
\(\left(\dfrac{5}{8}+\dfrac{-2}{7}\right):\dfrac{3}{4}+\left(\dfrac{3}{8}-\dfrac{5}{7}\right):\dfrac{3}{4}\\ =\left(\dfrac{5}{8}+\dfrac{-2}{7}\right)\times\dfrac{4}{3}+\left(\dfrac{3}{8}-\dfrac{5}{7}\right)\times\dfrac{4}{3}\\ =\dfrac{4}{3}\times\left(\dfrac{5}{8}+\dfrac{-2}{7}+\dfrac{3}{8}-\dfrac{5}{7}\right)\times\dfrac{4}{3}\\ =\left(1-1\right)\times\dfrac{4}{3}\\ =0\times\dfrac{4}{3}\\ =0\)
d)
\(M=\dfrac{\dfrac{3}{4}-\dfrac{3}{5}+\dfrac{3}{7}+\dfrac{3}{11}}{\dfrac{13}{4}-\dfrac{13}{5}+\dfrac{13}{7}+\dfrac{13}{11}}\\ =\dfrac{3\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{11}\right)}{13\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{11}\right)}\\ =\dfrac{3}{13}\)
\(a.\left(-\dfrac{9}{34}\right)\cdot\dfrac{17}{4}=-\dfrac{9}{8}\\ b.\left(-\dfrac{20}{41}\right)\cdot\left(-\dfrac{4}{5}\right)=\dfrac{16}{41}\\ c.1\dfrac{1}{7}\cdot\left(-3\dfrac{1}{2}\right)=\dfrac{8}{7}\cdot\left(-\dfrac{7}{2}\right)=-4\\ d.\left(-\dfrac{5}{2}\right):\dfrac{3}{4}=\left(-\dfrac{5}{2}\right)\cdot\dfrac{4}{3}=-\dfrac{10}{3}\\ e.\left(-\dfrac{3}{4}\right):\left(-1\dfrac{1}{3}\right)=\left(-\dfrac{3}{4}\right)\cdot\left(-\dfrac{3}{4}\right)=\dfrac{9}{16}\\ g.\left(-5\right):\left(-2\dfrac{1}{2}\right)=\left(-5\right)\cdot\left(-\dfrac{2}{5}\right)=2\)
\(a)-\dfrac{9}{34}\times\dfrac{17}{4}\\ =\dfrac{-9}{17\times2}\times\dfrac{17}{4}\\ =\dfrac{-9}{8}\\ b)-\dfrac{20}{41}\times-\dfrac{4}{5}\\ =\dfrac{4\times5}{41}\times\dfrac{-4}{5}\\ =-\dfrac{16}{41}\\ c)1\dfrac{1}{7}\times\left(-3\dfrac{1}{2}\right)\\ =\dfrac{8}{7}\times\dfrac{-7}{2}\\ =-4\\ d)-\dfrac{5}{2}:\dfrac{3}{4}\\ =-\dfrac{5}{2}\times\dfrac{4}{3}\\ =\dfrac{-10}{3}\\ e)-\dfrac{3}{4}:\left(-1\dfrac{1}{3}\right)\\ =-\dfrac{3}{4}:-\dfrac{4}{3}\\ =-\dfrac{3}{4}\times-\dfrac{3}{4}\\ =\dfrac{9}{16}\\ g)-5:\left(-2\dfrac{1}{2}\right)\\ =-5:-\dfrac{5}{2}\\ =-5\times-\dfrac{2}{5}\\ =2\)
Bài 1
1 two pieces of furniture
2 Two plates of pasta
3 four sheets of paper
4 Three glasses of lemonade
5 Two cups of yoghurt
6 Three bottles of oil
7 Two tubes of toothpaste
8 Five steaks of salmon
Số chữ số cần dùng để đánh số cho trang có 1 chữ số là:
(9-1+1)x1=9(chữ số)
Số chữ số cần dùng để đánh số cho trang có 2 chữ số là:
(99-10+1)x2=180(chữ số)
SỐ chữ số cần dùng để đánh số cho trang có 3 chữ số là:
(100-100+1)x3=3(chữ số)
Số chữ số cần dùng là:
9+180+3=192(chữ số)
Lời giải:
a.
$4x^2-6x=0$
$\Leftrightarrow 2x(2x-3)=0$
$\Leftrightarrow 2x=0$ hoặc $2x-3=0$
$\Leftrightarrow x=0$ hoặc $x=\frac{3}{2}$
b.
$9x^2-6x+1=0$
$\Leftrightarrow (3x-1)^2=0$
$\Leftrightarrow 3x-1=0$
$\Leftrightarrow x=\frac{1}{3}$
c.
$x^2-25=x+5$
$\Leftrightarrow (x-5)(x+5)=x+5$
$\Leftrightarrow (x+5)(x-5-1)=0$
$\Leftrightarrow (x+5)(x-6)=0$
$\Leftrightarrow x+5=0$ hoặc $x-6=0$
$\Leftrightarrow x=-5$ hoặc $x=6$
d.
$(5x-3)^2=(5-3x)^2$
$\Leftrightarrow (5x-3)^2-(5-3x)^2=0$
$\Leftrightarrow (5x-3-5+3x)(5x-3+5-3x)=0$
$\Leftrightarrow (2x-8)(2x+2)=0$
$\Leftrightarrow 2x-8=0$ hoặc $2x+2=0$
$\Leftrightarrow x=4$ hoặc $x=-1$
chiều rộng mảnh vườn là: 12 x 3/4 = 9
a) chu vi mảnh vườn là: (12 + 9) x 2 = 42
b) diện tích mảnh vườn là: 12 x 9 = 108
c) diện tích trồng rau là: 108 x 2/3 = 72
a) Chiều rộng mảnh vườn là:
`3/4 xx 12 = 9`
Chu vi mảnh vườn là:
(12 + 9) x 2 = 42
b) Diện tích mành vườn là:
12 x 9 = 108
c) Diện tích trồng rau là:
`2/3 xx 108 = 72` '
ĐS: ...