mn trả lời chi tiết cho e vs ạ

ƯC(48; 54; 66)

Ta có: 48 = 2⁴.3;   54 = 2.3³; 66 = 2.3.11

ƯCLN(48; 54; 66) =  2.3 = 6

ƯC(48; 54; 66) = { 1; 2; 3; 6}

2115 = (7.3)15 = 715.315

275.498 = (33)5.(72)8 = 315.716 = 7.315.715 > 315.715 = 2115

=> 275.498 > 2115.

tick cho mink nhé 😊

72,9 + 99 + 72 + 0,9

= (72,9 + 0,9) + (99 + 72)

= 73,8 + 171

= 244,8

72,9+99+72+0,9= 244,8

Ta có: A = 2 + 22 + 23 + … + 22017

2A = 2.( 2 + 22 + 23 + … + 22017)

2A = 22 + 23 + 24 + … + 22018

2A – A = (22 + 23 + 24 + … + 22018) – (2 + 22 + 23 + … + 22017)

A = 22018 – 2

Vậy A = 22018 – 2

tick cho mink nhé

😊

54\(⋮\) \(x\);   72 ⋮ \(x\);     90 ⋮ \(x\) ⇒ \(x\) \(\in\) ƯC(54; 72; 90) ⇒ \(x\)\(\in\)ƯCLN(54;72;90)

54 = 2.3²;        72 = 2³.3²; 90 = 2.3².5

ƯCLN(54; 72; 90) = 2.3² = 18

\(x\in\)Ư(18) = { 1; 2; 3; 6; 9; 18}

Ta có:

\(100=2^2.5^2\)\(;150=2.3.5^2\)

\(ƯCLN\left(100;150\right)=2.5^2=50\)

Ta có:

\(35=5.7;75=3.5^2\)

\(ƯCLN\left(35;75\right)=5\)

(1 - \(\dfrac{1}{2}\)) \(\times\)(1 - \(\dfrac{1}{3}\)) = \(\dfrac{1}{2}\) \(\times\) \(\dfrac{2}{3}\) = \(\dfrac{1}{3}\)

\(A=\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{149.150}\)

\(A=\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{149}-\dfrac{1}{150}\)

\(A=\dfrac{1}{1}-\dfrac{1}{150}\)

\(A=\dfrac{150}{150}-\dfrac{1}{150}\)

\(A=\dfrac{149}{150}\)