tính :\(\frac{\text{101+100+99+98+...+3+2+1}}{\text{101-100+99-98+...+3-2+1}}\)
mình đang cần gấp , ai làm nhanh mình tick cho
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\(S=1+2+2^2+...+2^{99}\)
\(S=\left(1+2\right)+\left(2^2+2^3\right)+...+\left(2^{98}+2^{99}\right)\)
\(S=3+2^2.3+...+2^{98}.3\)
\(=3\left(1+2^2+...+2^{98}\right)⋮3\)
1. + There is a TV on the table.
- There isn't a TV on the table.
? Is there a TV on the table ?
2. + There is a brown dog in the kitchen
- There isn't ____________________.
? Is there ____________________?
3. + There is a boy in front of the cupboard.
- There isn't_______________________.
? Is there _______________________.?
4. + There is a bath in the bathroom.
- There isn't__________________.
? Is there __________________?
5. +There are lamps in the bedroom.
- There aren't__________________
? Are there ___________________?
Cau 1.
-There is a tv on the table.
there is not a tv on the table
Is there a tv on the table?
Cau 2
-There is a brown dog in the kitchen
-There is not a brown dog in the kitchen
-Is there brown dog in the kitchen?
3^x-1 + 5.3^x-1 = 162
3^x-1. (1+5) = 162
3^x-1 =27
3^x-1 = 3^3
x-1 =3
x = 4
Vậy x=4
\(\left(x-2\right)^{x+2}=\left(x-2\right)^{x+1}\)
\(\left(x-2\right)^{x+2}-\left(x-2\right)^{x+1}=0\)
\(\left(x-2\right)^{x+1}\left(x-2-1\right)=0\)
\(\left(x-2\right)^{x+1}\left(x-3\right)=0\)
\(\Rightarrow\orbr{\begin{cases}\left(x-2\right)^{x+1}=0\\x-3=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x-2=0\\x=3\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=2\\x=3\end{cases}}\)
Vậy x = { 2; 3 }
\(\left(x-2\right)^{x+2}=\left(x-2\right)^{x+1}\)
\(\left(x-2\right)^{x+2}-\left(x-2\right)^{x+1}=0\)
\(\left(x-2\right)^{x+1}\left(x-2-1\right)=0\)
\(\Rightarrow\hept{\begin{cases}x=2\\x=3\end{cases}}\)
1 I haven't seen him since 2016
2 We're having a great time in Cambonica!!
\(\frac{101+100+99+98+...+3+2+1}{101-100+99-98+...+3-2+1}\)
\(=\frac{\frac{101.102}{2}}{51}\)
\(=101\)