\(\sqrt{x^2+2x+1}=x+2\)

\(\Rightarrow\sqrt{\left(x+1\right)^2}=x+2\)

\(\Rightarrow x+1=x+2\)

\(\Rightarrow x+1+x+2=0\)

\(\Rightarrow2x+3=0\)

\(\Rightarrow2x=-3\)

\(\Rightarrow x=-\frac{3}{2}\)

\(Taco:\)

\(\left(x+y\right)\left(y+z\right)=187\Leftrightarrow xy+xz+yy+yz=187\)

\(\left(y+z\right)\left(z+x\right)=154\Leftrightarrow yz+xy+zz+xz=154\)

\(\left(z+x\right)\left(x+y\right)=238\Leftrightarrow xz+zy+xx+xy=238\)

\(\Rightarrow\left(x+y\right)\left(y+z\right)+\left(x+z\right)\left(x+y\right)+\left(y+z\right)\left(z+x\right)=579\)

\(\Leftrightarrow xy+zx+yy+yz+yz+xy+zz+xz+xz+zy+xx+xy=579\)

\(\Leftrightarrow3\left(xz+xy+yz\right)+x^2+y^2+z^2=579\)

\(\left(z+x\right)\left(x+y\right)-\left(x+y\right)\left(y+z\right)=51\)

\(\Leftrightarrow\left(x+y\right)\left(x-y\right)=x^2-y^2=51\)

\(\left(z+x\right)\left(x+y\right)-\left(y+z\right)\left(x+z\right)=84\)

\(\Leftrightarrow\left(x+z\right)\left(x-z\right)=84\Leftrightarrow x^2-z^2=84\)

\(\Leftrightarrow y^2-z^2=33\)

đến đây tịt

ak tớ bt cách giải rồi cần thì ib ns tớ lm :v

\(\hept{\begin{cases}2x-y+2y=1\\3x+y+x=3\end{cases}}\)

\(\hept{\begin{cases}2x+y=1\\4x+y=3\end{cases}}\)\(\hept{\begin{cases}y=1-2x\\4x+y=3\end{cases}}\)\(\hept{\begin{cases}y=1-2x\\4x+1-2x=3\end{cases}}\)\(\hept{\begin{cases}y=1-2x\\2x+1=3\end{cases}}\)

\(\hept{\begin{cases}y=1-2x\\x=1\end{cases}}\)\(\hept{\begin{cases}y=-1\\x=1\end{cases}}\)

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