các bạn giải giúp mình với mình cần gấp

Mai lên hỏi cô giáo

Hình đâu????//

sao không có hình

\(\frac{144}{x+2}-\frac{100}{x}=2\)

\(\frac{144}{x-2}.x\left(x+2\right)-\frac{100}{x}.x\left(x+2\right)=2.x\left(x+2\right)\)

144x - 100(x + 2) = 2.x(x + 2)

x = 10

=> x = 10

K chắc nhá :w

\(ĐK:x\ne-2;x\ne0\)

\(\frac{144}{x+2}-\frac{100}{x}=2\)

\(\Leftrightarrow\frac{144}{x+2}-\frac{100}{x}-2=0\Leftrightarrow\frac{144x-100x-200-2x^2-4x}{\left(x+2\right)x}=0\)

\(\Leftrightarrow\frac{40x-2x^2-200}{\left(x+2\right)x}=0\Leftrightarrow40x-2x^2-200=0\Leftrightarrow20x-x^2-200=0\)

\(\Leftrightarrow-\left(20x-x^2-200\right)=0\Leftrightarrow x^2-20x+200=0\)

\(\Leftrightarrow\left(x-10\right)^2+100=0\left(\text{vô lí}\right)\)

\(\text{Vậy: pt vô nghiệm}\)

\(P=\frac{4\sqrt{x}+3}{x+\sqrt{x}}+\frac{\sqrt{x}}{\sqrt{x}+1}\)

\(P=\frac{4\sqrt{x}+3}{\sqrt{x}\left(\sqrt{x}+1\right)}+\frac{\sqrt{x}}{\sqrt{x}+1}=\frac{4\sqrt{x}+3}{\sqrt{x}\left(\sqrt{x}+1\right)}+\frac{x}{\sqrt{x}\left(\sqrt{x}+1\right)}\)

\(=\frac{x+4\sqrt{x}+3}{\sqrt{x}\left(\sqrt{x}+1\right)}\inℤ\Leftrightarrow x+4\sqrt{x}+3⋮\sqrt{x}\)

Giải tiếp nhé sau đó thử chọn :V

\(p=\frac{4\sqrt{x}+3}{x+\sqrt{x}}+\frac{\sqrt{x}}{\sqrt{x}+1}\)

\(=\frac{4\sqrt{x}+3}{\sqrt{x}\left(\sqrt{x}+1\right)}+\frac{x}{\sqrt{x}\left(\sqrt{x}+1\right)}\)

\(=\frac{x+\sqrt{x}+3\sqrt{x}+3}{\sqrt{x}\left(\sqrt{x}+1\right)}=\frac{\left(\sqrt{x}+3\right)\left(\sqrt{x}+1\right)}{\sqrt{x}\left(\sqrt{x}+1\right)}\)

\(=\frac{\sqrt{x}+3}{\sqrt{x}}=1+\frac{3}{\sqrt{x}}\)

Để \(x\in Z\Rightarrow P\in Z\)

\(\Rightarrow\sqrt{x}\inƯ\left(3\right)= \left\{-3;3\right\}\)

\(\Leftrightarrow x=9\left(t.mĐKXĐ\right)\)