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I
1 A
2 D
3 B
4 C
5 C
II
1 the best
2 hotter
3 the happiest
4 more expensive
5 the most comfortable
6 larger
7 noisier
8 is the highest
9 more boring
10 the youngest
II
1 are staying - am playing - is reading
2 does your library have - has
3 is
4 goes - likes - doens't like
5 do we find
IV
1 important
2 has
3 see
4 learn
5 help
6 problems
7 libraries
8 use
11 does => do
12 are => is
13 speaks => is speaking
14 am going => go
15 likes => like
16 are => is
17 stay => are staying
18 knows => know
19 am going => go
20 look => am looking
21 leaves => is leaving
22 is => am
23 walk => walks
24 are => is
25 goes => go
26 is going => go
27 play => are playing
28 is crying => cries
29 do not=> am not doing
30 do => does
12 (x - 4) + 13 (x - 4) = 50
<=> (x - 4) (12 + 13) = 50
<=> 25 (x - 4) = 50
<=> x - 4 = 2
<=> x = 6
12(x-4)+13(x-4)=50
=>25(x-4)=50
=>\(x-4=\dfrac{50}{25}=2\)
=>x=2+4=6
\(16\left(143-x\right)-2\left(143-x\right)=1414\)
=>\(14\left(143-x\right)=1414\)
=>143-x=1414:14=101
=>x=143-101=42
16 x (143 - \(x\)) - 2 x (143 - \(x\)) = 1414
(143 - \(x\)) x (16 - 2) = 1414
(143 - \(x\)) x 14 = 1414
143 - \(x\) = 1414 : 14
143 - \(x\) = 101
\(x\) = 143 - 101
\(x\) = 42
Vậy \(x=42\)
2x-31=4646:46
=>2x-31=101
=>2x=31+101=132
=>\(x=\dfrac{132}{2}=66\)
(x+2)+(x+4)+...+(x+20)=260
=>10x+(2+4+...+20)=260
=>\(10x+2\left(1+2+...+10\right)=260\)
=>\(10x+2\cdot10\cdot\dfrac{11}{2}=260\)
=>\(10x+110=260\)
=>10x=150
=>\(x=\dfrac{150}{10}=15\)
Số nhóm trong phép tỉnh tổng trên là:
`(20 - 2) : 2 + 1 = 10` (nhóm)
`(x + 2) + (x+4) + ... + (x+20) = 260`
`=> 10x + (2+4+...+20) = 260`
`=> 10x + (20+2) . 10 = 260`
`=> 10x + 22. 10 = 260`
`=> 10x + 220 = 260`
`=> 10x = 260 - 220`
`=> 10x = 40`
`=> x = 40 : 10`
`=> x = 4`
Vậy `x = 4`
(x+3)+(x+6)+...+(x+51)=493
=>17x+(3+6+...+51)=493
=>\(17x+3\left(1+2+...+17\right)=493\)
=>\(17x+3\cdot17\cdot\dfrac{18}{2}=493\)
=>\(17x+51\cdot9=493\)
=>17x=34
=>x=2