a, 2/3 + 1/3 : x = 3/5

1/3 : x = -1/15

x = -1/45

b, x - 5/9 = -2/3

x = -1/9

\(A=1+\dfrac{1}{8}+\dfrac{1}{24}+\dfrac{1}{48}+\dfrac{1}{80}+\dfrac{1}{120}\)

\(A=\dfrac{1}{2.4}+\dfrac{1}{4.6}+\dfrac{1}{6.8}+\dfrac{1}{8.10}+\dfrac{1}{10.12}\)

\(2A=\dfrac{2}{2.4}+\dfrac{2}{4.6}+\dfrac{2}{6.8}+\dfrac{2}{8.10}+\dfrac{2}{10.12}\)

\(2A=1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{6}+...+\dfrac{1}{10}-\dfrac{1}{12}\)

\(2A=1-\dfrac{1}{12}\)

\(2A=\dfrac{11}{12}\)

\(A=\dfrac{11}{12}:2=\dfrac{11}{24}\)

\(A=1+\dfrac{1}{8}+\dfrac{1}{24}+\dfrac{1}{48}+\dfrac{1}{80}+\dfrac{1}{120}\)

\(=1+\dfrac{1}{2\cdot4}+\dfrac{1}{4\cdot6}+\dfrac{1}{6\cdot8}+\dfrac{1}{8\cdot10}+\dfrac{1}{10\cdot12}\)

\(=1+\dfrac{1}{2}\left(\dfrac{2}{2\cdot4}+\dfrac{2}{4\cdot6}+...+\dfrac{2}{10\cdot12}\right)\)

\(=1+\dfrac{1}{2}\left(\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{6}+...+\dfrac{1}{10}-\dfrac{1}{12}\right)\)

\(=1+\dfrac{1}{2}\left(\dfrac{1}{2}-\dfrac{1}{12}\right)=1+\dfrac{1}{2}\cdot\dfrac{5}{12}=1+\dfrac{5}{24}=\dfrac{29}{24}\)

\(\dfrac{7}{-3}\) là phân số.

Trong các số trên, \(\dfrac{7}{-3}\) là phân số.

\(B=\dfrac{1}{29}+\dfrac{2}{28}+...+\dfrac{28}{2}+\dfrac{29}{1}\)

\(=\left(\dfrac{1}{29}+1\right)+\left(\dfrac{2}{28}+1\right)+...+\left(\dfrac{28}{2}+1\right)+1\)

\(=\dfrac{30}{29}+\dfrac{30}{28}+...+\dfrac{30}{2}+\dfrac{30}{30}\)

\(=30\left(\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{30}\right)=30A\)

=>\(\dfrac{A}{B}=\dfrac{1}{30}\)

\(A=1+\dfrac{1}{1+2}+...+\dfrac{1}{1+2+...+8}\)

\(=\dfrac{2}{2}+\dfrac{1}{2\cdot\dfrac{3}{2}}+...+\dfrac{1}{8\cdot\dfrac{9}{2}}\)

\(=\dfrac{2}{1\cdot2}+\dfrac{2}{2\cdot3}+...+\dfrac{2}{8\cdot9}\)

\(=2\left(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{8\cdot9}\right)\)

\(=2\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{8}-\dfrac{1}{9}\right)\)

\(=2\left(1-\dfrac{1}{9}\right)=2\cdot\dfrac{8}{9}=\dfrac{16}{9}\)

file:///C:/Users/Admin/Downloads/MicrosoftWindows.Client.CBS_cw5n1h2txyewy!InputApp/GraduationHappyGIF.gif

M là trung điểm của AB

=>\(MA=MB=\dfrac{AB}{2}=3\left(cm\right)\)

B là trung điểm của ME

=>\(ME=2\cdot MB=2\cdot3=6\left(cm\right)\)

M là trung điểm của AB

=>\(MA=MB=\dfrac{6}{2}=3\left(cm\right)\)

B là trung điểm của ME

=>\(ME=2\cdot MB=6\left(cm\right)\)