6. D

7. B

8. B

9. D

10. C

11. C

12. D

13. A

14. C

Bn @Olm Hỏng rồi :>>>

Mk cho bn đủ 3 lần rồi nên mk ko thêm đc

Dù sao mk cx cảm ơn bn

\(\left|3x-5\right|+\left(2y+5\right)^{208}+\left(4z-3\right)^{20}\le0\)

\(\Leftrightarrow\hept{\begin{cases}3x-5=0\\2y+5=0\\4z-3=0\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}x=\frac{5}{3}\\y=-\frac{5}{2}\\z=\frac{3}{4}\end{cases}}\)

goolglo

c bn ơi

TL:

1-c ; 2-d ; 3-b ; 4-d ; 5-a

_HT_

TL:
 

1 + 1 = 3

1 + 1 = 11

Cái dạng này thì có nhiều câu trả lời mà

........................

_____________( ' _ ' ) ______________

 Đúng ko???

1+1=11 à bn

 Xin chào 

báo cáo giang nha

\(\left(\frac{2}{3}\right)^{17}:\left(\frac{2}{3}\right)^{15}+\frac{4}{9}.\left(-\frac{1}{2}\right)^3\)

\(=\left(\frac{2}{3}\right)^{17-15}+\frac{4}{9}.\left(-\frac{1}{8}\right)\)

\(=\left(\frac{2}{3}\right)^2+\frac{4}{9}.\left(-\frac{1}{8}\right)\)

\(=\frac{4}{9}+\frac{4}{9}.\left(-\frac{1}{8}\right)\).

\(=\frac{4}{9}.1+\frac{4}{9}.\left(-\frac{1}{8}\right)\)

\(=\frac{4}{9}.\left(-\frac{1}{8}+1\right)\)

\(=\frac{4}{9}.\frac{7}{8}\)

\(=\frac{7}{18}\)

\(\left(\frac{2}{3}\right)^{17}:\left(\frac{2}{3}\right)^{15}+\frac{4}{9}.\left(-\frac{1}{2}\right)^3\)

\(=\left(\frac{2}{3}\right)^{17-15}+\frac{2^2}{9}.\frac{-1}{2^3}\)

\(=\left(\frac{2}{3}\right)^2+\frac{-1}{18}\)\(=\frac{4}{9}-\frac{1}{18}=\frac{7}{18}\)