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Phản ứng: 2NOCl(g) -> 2NO(g) + Cl2(g)
Biểu thức tính tốc độ trung bình (vtb):
Tổng hợp lại, biểu thức đầy đủ là:
vtb = - (1/2) * (Δ[NOCl] / Δt) = + (1/2) * (Δ[NO] / Δt) = + (Δ[Cl2] / Δt)
Trong đó:
\(NaOH+HCl\rightarrow NaCl+H_2O\)
0,01 0,01 0,01 0,01
số mol dung dịch HCl là:
\(C_M=\dfrac{n_{HCl}}{V_{HCl}}⇒\:n_{HCl}=C_M\cdot V_{HCl}=0,2\cdot0,05=0,01\left(mol\right)\)
thể tích NaOH cần thiết để trung hoà là:
\(C_{M_{NaOH}}=\dfrac{n_{NaOH}}{V_{NaOH}}⇒\:V_{NaOH}=\dfrac{n_{NaOH}}{C_{M_{NaOH}}}=\dfrac{0,01}{0,1}=0,1\left(L\right)\)
Số mol HCl được tính theo công thức:
\(n \left(\right. \text{HCl} \left.\right) = C \times V = 0 , 2 \textrm{ } \text{mol}/\text{l} \times 0 , 05 \textrm{ } \text{l} = 0 , 01 \textrm{ } \text{mol} .\)Theo phương trình phản ứng, \(n \left(\right. \text{NaOH} \left.\right) = n \left(\right. \text{HCl} \left.\right)\), vì tỉ lệ mol là 1:1.
\(n \left(\right. \text{NaOH} \left.\right) = 0 , 01 \textrm{ } \text{mol} .\)Thể tích dung dịch NaOH được tính theo công thức:
\(V \left(\right. \text{NaOH} \left.\right) = \frac{n \left(\right. \text{NaOH} \left.\right)}{C \left(\right. \text{NaOH} \left.\right)} = \frac{0 , 01 \textrm{ } \text{mol}}{0 , 1 \textrm{ } \text{mol}/\text{l}} = 0 , 1 \textrm{ } \text{l} = 100 \textrm{ } \text{ml} .\)Thể tích dung dịch NaOH cần thiết để trung hòa hết lượng HCl là 100 ml.
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1 While I was riding home, I saw an accident
2 When he was young, he smoked a lot
3 While Jane was taking a bath, the phone rang three times
4 While I was having lunch, James arrived
5 While we were having dinner, the light went out
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