17:5x7+1,4%x5200+310x14%

=17x1,4+1,4x52+1,4x31

=1,4x(17+52+31)

=1,4x100=140

\(y\times7,5+y+y\times91,4+y:10=257,8\)

\(y\times7,5+y\times1+y\times91,4+y\times0,1=257,8\)

\(y\times\left(7,5+1+91,4+0,1\right)=257,8\)

\(y\times100=257,8\)

\(y=257,8:100\)

\(y=2,578\)

y x 7,5 + y + y x 91,4 + y : 10 = 257,8

y x 7,5 + y + y x 91,4 + y x 0,1 = 257,8

y x (7,5 + 1 + 91,4 + 0,1) = 257,8

y x 100 = 257,8

y = 257,8 : 100

y = 2,578

1075

Thời gian ô tô đi hết quãng đường AB:

(11 giờ 20 phút - 1 giờ 30 phút - 6 giờ 30 phút) : 2 = 2 giờ 10 phút = 13/6 (giờ)

Độ dài quãng đường AB:

69,6 × 13/6 = 150,8 (km)

$y:0,125+y:10+y\times1,9=202,3$

$y\times8+y\times0,1+y\times1,9=202,3$

$y\times(8+0,1+1,9)=202,3$

$y\times(8+2)=202,3$

$y\times10=202,3$

$y=202,3:10$

$y=20,23$

\(y:0,125+y:10+y\times1,9=202,3\)

\(y\times8+y\times01,+y\times1,9=202,3\)

\(y\times\left(8+0,1+1,9\right)=202,3\)

\(y\times10=202,3\)

\(y=202,3:10\)

\(y=20,23\)

\(1\dfrac{2}{24}\text{x}\text{ }5\dfrac{2}{5}\text{x}2\text{x}3\dfrac{7}{9}\text{x}2\dfrac{2}{17}\)

\(=\dfrac{13}{12}\text{x}\dfrac{27}{5}\text{x}2\text{x}\dfrac{34}{9}\text{x}\dfrac{36}{17}\)

\(=\dfrac{13}{12}\text{x}2\text{x}\dfrac{27}{9}\text{x}\dfrac{34}{17}\text{x}\dfrac{36}{5}\)

\(=\dfrac{13}{6}\text{x}3\text{x}2\text{x}\dfrac{36}{5}=13\text{x}\dfrac{36}{5}=\dfrac{468}{5}\)

\(2\dfrac{2}{17}\text{x}1\dfrac{1}{24}\text{x}5\dfrac{2}{5}\text{x}3\dfrac{7}{9}\text{x}2\)

\(=\dfrac{36}{17}\text{x}\dfrac{25}{24}\text{x}\dfrac{27}{5}\text{x}\dfrac{34}{9}\text{x}2\)

\(=\dfrac{36}{24}\text{x}\dfrac{25}{5}\text{x}\dfrac{27}{9}\text{x}\dfrac{34}{17}\text{x}2\)

\(=\dfrac{3}{2}\text{x}5\text{x}3\text{x}2\text{x}2=90\)

Số số hạng là x-10+1=x-9(số)

Tổng là \(\dfrac{\left(x-9\right)\left(x+10\right)}{2}\)

Do đó, ta có: \(\dfrac{\left(x-9\right)\left(x+10\right)}{2}=5106\)

=>\(\left(x-9\right)\cdot\left(x+10\right)=5106\cdot2=10212\)

=>\(x^2+x-90=10212\)

=>\(x^2+x-10302=0\)

=>\(\left[{}\begin{matrix}x=101\left(nhận\right)\\x=-102\left(loại\right)\end{matrix}\right.\)

vậy: x=101

Chiều cao của bể sau khi cho thêm hòn đá vào thì tăng thêm:

12-9=3(cm)

Thể tích của hòn đá cảnh là:

3x30x15=1350(cm³)

X × 3 + X × 4 + X : 3 + X : 4 = 546

X × 3 + X × 4 + X × 1/3 + X × 1/4 = 546

X × (3 + 4 + 1/3 + 1/4) = 546

X × 91/12 = 546

X = 546 : 91/12

X = 72

X × 3 + X × 4 + X : 3 + X : 4 = 546

X × 3 + X × 4 + X × 1/3 + X × 1/4 = 546

X × (3 + 4 + 1/3 + 1/4) = 546

X × 91/12 = 546

X = 546 : 91/12

X = 72

@_@