Tìm n thuộc N sao cho: 2n+7 chia hết cho n - 2
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Giải:
a,
A = {0; 5; 10; 15; 20; 25; 30; 35; 40; 45; 50; ...}
B = {0; 10; 20; 30; 40; 50; ...}
=> A ∩ B = {0; 10; 20; 30; 40; 50; ...}
Phần còn lại làm tương tự.
số đó là 60 nha bạn
ước là 1,2,3,4,5,6,10,12,15,20,30,60
\(\left|-120\right|+45-31-75\)
\(=120+45-31-75\)
\(=59\)
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n=3
ok ko phải mình chứ
ta có 2n+7 chia hết cho n-2
=>2n-4+4+7 chia hết cho n-2
=>(2n-4)+11 chia hết cho n-2
=>2(n-2)+11 chia hết cho n-2
vì n-2 chia hết cho n-2 nên 2(n-2) chia hết cho n-2
=>11 chia hết cho n-2
=> n-2 thuộc Ư(11)
Mà Ư(11)={1;11} nên n-2 bằng 1 hoặc n-2 bằng 11
+Nếu n-2=1
n=1+2=3
+Nếu n-2=11
n=1+2=13
Vậy n thuộc {3;13}