2.24.25+3.31.16+6.2.8.1
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22.3 - (12000 + 8): 32
= 12 - (1+8): 32
= 12 - 9: 9
= 12 - 1
= 11
55 : 52 + 32.33: 34 - 82:43
= 53 + 3 - 26: 26
= 125 + 3 -1
= 127
\(a)\dfrac{x}{3}=\dfrac{3}{2}.\dfrac{1}{4}\)
\(\dfrac{x}{3}=\dfrac{3}{8}\)
\(8x=9\)
\(x=\dfrac{9}{8}\)
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\(b)\dfrac{x}{5}=\dfrac{-1}{3}:\dfrac{7}{2}\)
\(\dfrac{x}{5}=\dfrac{-2}{21}\)
\(21x=-10\)
\(x=\dfrac{-10}{21}\)
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\(c)x+\dfrac{2}{3}=\dfrac{4}{3}-\dfrac{1}{6}\)
\(x+\dfrac{2}{3}=\dfrac{7}{6}\)
\(x=\dfrac{7}{6}-\dfrac{2}{3}\)
\(x=\dfrac{1}{2}\)
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\(d)x-\dfrac{5}{2}=\dfrac{7}{2}-4\)
\(x-\dfrac{5}{2}=\dfrac{-1}{2}\)
\(x=\dfrac{-1}{2}+\dfrac{5}{2}\)
\(x=2\)
a) \(\dfrac{x}{3}=\dfrac{3}{2}\cdot\dfrac{1}{4}\)
\(\dfrac{x}{3}=\dfrac{3}{8}\)
\(x=\dfrac{3\cdot3}{8}\)
\(x=\dfrac{9}{8}\)
b) \(\dfrac{x}{5}=\dfrac{-1}{3}:\dfrac{7}{2}\)
\(\dfrac{x}{5}=\dfrac{-1}{3}\cdot\dfrac{2}{7}\)
\(\dfrac{x}{5}=\dfrac{-2}{21}\)
\(x=\dfrac{-2\cdot5}{21}\)
\(x=-\dfrac{10}{21}\)
c) \(x+\dfrac{2}{3}=\dfrac{4}{3}-\dfrac{1}{6}\)
\(\dfrac{6x}{6}+\dfrac{2\cdot2}{3\cdot2}=\dfrac{4\cdot2}{3\cdot2}-\dfrac{1}{6}\)
\(\dfrac{6x}{6}+\dfrac{4}{6}=\dfrac{8}{6}-\dfrac{1}{6}\)
\(\dfrac{6x+4}{6}=\dfrac{7}{6}\)
\(\dfrac{6x+4}{6}-\dfrac{7}{6}=0\)
\(\dfrac{6x+4-7}{6}=0\)
\(\dfrac{6x-3}{6}=0\)
\(6x-3=0\)
\(6x=3\)
\(x=\dfrac{3}{6}=\dfrac{1}{2}\)
2.2.6.a.3.a.a = 23. 32 . a3
16.4.4.2.2.8 = 46 . 2 a.a.2.4.8 = a2 . 26
\(\dfrac{-4}{17}+\dfrac{5}{19}+\dfrac{-13}{17}+\dfrac{14}{19}+\dfrac{3}{115}\)
\(=(\dfrac{-4}{17}+\dfrac{-13}{17})+(\dfrac{5}{19}+dfrac{14}{19})+\dfrac{3}{115}\)
\(=\dfrac{-17}{17}+\dfrac{19}{19}+\dfrac{3}{115}\)
\(=-1+1+\dfrac{3}{115}=\dfrac{3}{115}\)
2.2.6.a.3.a.a = 23. 32 . a3
16.4.4.2.2.8 = 46 . 2 a.a.2.4.8 = a2 . 26
Số bi lúc sau ở túi phải là:
165+135:2=150(viên)
Số bi ở túi phải sau khi cho là:
150:2=75(viên)
Số bi ban đầu ở túi trái là:
165-135:2+75:2=45(viên)
Số bi ban đầu ở túi phải là:
165-45=120(viên)
2.24.25+3.31.16+6.2.8.1
= 48.25 + 48 . 31 + 48 . 2
= 48 . ( 25 + 31 + 2 ) =48 . 58 =2784
2.24.25 + 3.31.16 + 6.2.8.1
= 48.25 + 48 .31 + 48.2
= 48.( 25 + 31 + 2)
= 48. 58
= 2784