Environment refers to the natural surroundings and conditions in which we live. Unfortunately, this Environment has come under serious threat. This threat is almost entirely due to human activities. These human activities have certainly caused serious damage to the Environment. Most noteworthy, this damage risks the survival of living things on Earth. Therefore, there is an urgent need to save the Environment.

First of all, planting trees should be given massive attention. Above all, a tree is the source of oxygen. Unfortunately, due to construction, many trees have been cut down. This certainly reduces the amount of oxygen in the environment. Growing more trees means more oxygen. Hence, growing more trees would mean better life quality.

Similarly, people must give attention to forest conservation. Forests are vital for the Environment. However, deforestation certainly reduces the area of forests around the World. The government must launch programs to conserve the forests. The government must make harming forests a criminal offense.

Soil conservation is yet another important way to save the Environment. For this, there must be control of landslides, floods, and soil erosion. Furthermore, there should also be afforestation and tree plantation to conserve the soil. Also, terrace farming and using natural fertilizers are some more ways.

Waste management is a powerful way of protecting the environment. There must be proper disposal of wastes. Most noteworthy, this would help to keep the surroundings healthy. The government must ensure to clean the streets and other polluted land areas. Furthermore, there should be toilets in every house. Also, the government must provide enough public toilets.

Pollution is probably the biggest danger to the Environment. Smoke, dust, and harmful gases cause air pollution. These causes of air pollution come from industries and vehicles mostly. Furthermore, Chemicals and pesticides cause land and water pollution.

Gọi tọa độ các điểm A; B; C lần lượt là \(A\left(a;0;0\right);B\left(0;b;0\right);C\left(0;0;c\right)\) với \(a;b;c>0\)

Phương trình (P) theo đoạn chắn:

\(\dfrac{x}{a}+\dfrac{y}{b}+\dfrac{c}{z}=1\) (1)

Do (P) qua M nên: \(\dfrac{1}{a}+\dfrac{2}{b}+\dfrac{3}{c}=1\)

ÁP dụng BĐT Cô-si:

\(1=\dfrac{1}{a}+\dfrac{2}{b}+\dfrac{3}{c}\ge3\sqrt[3]{\dfrac{6}{abc}}\Rightarrow abc\ge162\)

\(\Rightarrow V_{OABC}=\dfrac{1}{6}abc=27\)

Dấu "=" xảy ra khi \(\dfrac{1}{a}=\dfrac{2}{b}=\dfrac{3}{c}\Rightarrow\left\{{}\begin{matrix}b=2a\\c=3a\end{matrix}\right.\) 

\(\Rightarrow\dfrac{1}{a}+\dfrac{2}{2a}+\dfrac{3}{3a}=1\Rightarrow a=3\Rightarrow b=6;c=9\)

Thế vào (1): \(\dfrac{x}{3}+\dfrac{y}{6}+\dfrac{z}{9}=1\Leftrightarrow6x+3y+2z-18=0\)

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W = 1/2 CU₀² = 1/2 CU²+1/2LI²=> I = \(\dfrac{\sqrt{5}}{5}\) 

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\(y'=x^2-mx+2m=0\) (1)

Hàm nghịch biến trên một đoạn có độ dài bằng 3 khi và chỉ khi:

\(\left\{{}\begin{matrix}\Delta=m^2-8m>0\\\left|x_1-x_2\right|=3\\\end{matrix}\right.\) trong đó \(x_1;x_2\) là 2 nghiệm của (1)

\(\Leftrightarrow\left\{{}\begin{matrix}\left[{}\begin{matrix}m< 0\\m>8\end{matrix}\right.\\\left(x_1+x_2\right)^2-4x_1x_2=9\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}\left[{}\begin{matrix}m< 0\\m>8\end{matrix}\right.\\m^2-8m=9\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}m=-1\\m=9\end{matrix}\right.\)

$y^{\prime }=x^2-mx+2m=0$ (1)

Hàm nghịch biến trên một đoạn có độ dài bằng 3 khi và chỉ khi:

$\{\begin{array}{c}\Delta =m^2-8m>0\\ \left|x^1-x^2\right|=3\end{array}$ trong đó $x^1;x^2$ là 2 nghiệm của (1)

$\iff \{\begin{array}{c}[\begin{array}{c}m<0\\ m>8\end{array}\\ {\left(x^1+x^2\right)}^2-4x^1{x}^2=9\end{array}$

$\iff \{\begin{array}{c}[\begin{array}{c}m<0\\ m>8\end{array}\\ m^2-8m=9\end{array}$ $\Rightarrow [\begin{array}{c}m=-1\\ m=9\end{array}$